CODEWITHSUNDEEP
javadatetimedate
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Reputation: 12538

How to check if a date in a list is most current

I have a List of news feed with date attached, I want to walkthrough the list to determine which of the news feed's date is most current - and so I can arrange the news in the order of most current.

Any I deas how to achieve this?

Upvotes: 1

Views: 1697

Answers (4)

Bohemian
Bohemian

Reputation: 425033

Sort the list using a Comparator based on the date of the item, then pick the first item using list.get(0).

Here's an compilable and runnable implementation:

static class NewsFeed {
    String news;
    Date date;

    private NewsFeed(String news, Date date) {
        this.news = news;
        this.date = date;
    }

    public String getNews() {
        return news;
    }

    public Date getDate() {
        return date;
    }
}

public static void main(String[] args) throws Exception {
    List<NewsFeed> list = new ArrayList<NewsFeed>();

    list.add(new NewsFeed("A", new Date(System.currentTimeMillis() - 1000)));
    list.add(new NewsFeed("B", new Date())); // This one is the "latest"
    list.add(new NewsFeed("C", new Date(System.currentTimeMillis() - 2000)));

    Collections.sort(list, new Comparator<NewsFeed>() {
        public int compare(NewsFeed arg0, NewsFeed arg1) {
            // Compare in reverse order ie biggest first
            return arg1.getDate().compareTo(arg0.getDate()); 
        }
    });
    NewsFeed latestNewsFeed = list.get(0);
    System.out.println(latestNewsFeed.getNews()); // Prints "B", as expected
}

Upvotes: 2

Jean Logeart
Jean Logeart

Reputation: 53829

Create a Comparator for the objects contained in your List and then call the Collections.sort method with this List to sort and the created Comparator as parameters.

Upvotes: 0

dimitrisli
dimitrisli

Reputation: 21391

You can Collections.sort your list of Feed classes passing a Comparator comparing to the dates that I am guessing are fields on your Feed class

Upvotes: 0

Peter Lawrey
Peter Lawrey

Reputation: 533530

The most natural way would be to either sort the List e.g. sort in descending order using Collections.sort() with a custom comparator. Or use PriorityQueue and extract out the next new time each time (useful if say you only want the 10 most recent)

Upvotes: 0

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