CODEWITHSUNDEEP
yamlazure-pipelinesazure-pipelines-yaml
Tomas Berger
Tomas Berger

Reputation: 145

Azure Pipeline: Make Jobs run on the same Agent from the same pool

I have a YAML script that looks something like this:

jobs:
- job: UnixBuild
  pool: 
    name: BuildMachinesUnix
  steps:
  - bash: echo "Build Unix"

- job: WinBuild
  pool: 
    name: BuildMachinesWindows
  steps:
  - bash: echo "Build Windows"

- job: UnixRelease
  dependsOn:
    - UnixBuild
    - WinBuild
  condition: and(succeeded('UnixBuild'), succeeded('WinBuild'))
  pool: 
    name: BuildMachinesUnix
  steps:
  - bash: echo "Release on Unix"

- job: WinRelease
  dependsOn:
    - UnixBuild
    - WinBuild
  condition: and(succeeded('UnixBuild'), succeeded('WinBuild'))
  pool: 
    name: BuildMachinesWindows
  steps:
  - bash: echo "Release on Windows"

Each Pool has several agent, and I want the Agent that took on the UnixBuild job to also handle the UnixRelease job, as all the files for that release is there, so that I don't needto rebuild it, in the release step, and the same goes from the WindowsBuild

Is such a thing possible, if so how?

If not, have any good suggestion for how to only release if both Unix and Windows succedes, without having to compile it twice?

Upvotes: 2

Views: 3588

Answers (1)

Leo Liu
Leo Liu

Reputation: 76928

I want the Agent that took on the UnixBuild job to also handle the UnixRelease job, as all the files for that release is there, so that I don't needto rebuild it, in the release step, and the same goes from the WindowsBuild

The answer is yes.

To resolve this issue, we could get the agent name from the UnixBuild job， then pass this as demands:

  - job: UnixBuild
    pool: 
      name: BuildMachinesUnix
    steps:
    - bash: echo "$(Agent.Name)"
    - bash: |
        echo "##vso[task.setvariable variable=someName;isOutput=true;]$(Agent.Name)"
      name: setVariable

  - job: UnixRelease
    dependsOn:
      - UnixBuild
      - WinBuild
    condition: and(succeeded('UnixBuild'), succeeded('WinBuild'))
    variables: 
      TestsomeName: $[ dependencies.UnixBuild.outputs['setVariable.someName'] ]
    pool: 
      name: BuildMachinesUnix
      demands:
      - Agent.Name -equals $(TestsomeName)
    steps:
    - bash: echo "$(TestsomeName)"

Upvotes: 7

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