CODEWITHSUNDEEP
phpoopinclude
John
John

Reputation: 7880

new class in included files

I have some classes, and that classes are included in index.php file , like :

<?php
 include("./includes/user.class.php");
 include("./includes/anotherclass.class.php");
?>

then I have :

  $layout = new layout();
  $layout->sampleMethod;

then in the body i have :

include("pages/samplePage.php");

then in that samplePage.php

i have to create new layout() again to use class functions, is there a way to use $layout->method in included file without create another object?

more code:

Layout class :

public function mkLayout()
  {
    include("pages/page.php");
  }
public function getPageUrl()
  {
    echo "PAGE URL";
  }

some of index.php :

<?php
  require_once("includes/layout.class.php");

  $layout = new layout();
  $layout->mkLayout();
?>

some of samplePage.php

  <?php
    $layout->getPageUrl();
   ?>

the samplePage.php returns :

Fatal error: Call to a member function getPageUrl() on a non-object in

Upvotes: 1

Views: 252

Answers (4)

afuzzyllama
afuzzyllama

Reputation: 6548

Going off what you have posted, if this is how your code looks:

<?php
    include("./includes/user.class.php");
    include("./includes/anotherclass.class.php");

    $layout = new layout();
    $layout->sampleMethod;

    include("pages/samplePage.php");
?>

$layout should already be declared in your pages/samplePage.php. Try doing var_dump($layout) in pages/samplePage.php and you'll see that it is already defined.

Why not just have a layout member inside of your class?

Upvotes: 0

Madara&#39;s Ghost
Madara&#39;s Ghost

Reputation: 174947

If you are using $layout in your included page, it should be working normally, assuming of course you declared $layout = new layout(); before you included samplePage.php.

If it doesn't work for you, try var_dump()ing it in your included page and see what you get there. Though it should be working as you are asking.

Edit!

After digging a little I found that wherever the file is included it inherits the scope of the function/method that used it, so use

global $layout;

Before you try to use methods and it should be working fine.

Manual Entry:

When a file is included, the code it contains inherits the variable scope of the line on which the include occurs. Any variables available at that line in the calling file will be available within the called file, from that point forward. However, all functions and classes defined in the included file have the global scope.

Useful links:

Upvotes: 1

Adrian Heine
Adrian Heine

Reputation: 4131

Maybe you are not really striving for object orientation in this example. Consider just using plain functions without classes.

Upvotes: 0

Umar Farouq Khattab
Umar Farouq Khattab

Reputation: 51

Nope, except you want to include the file that contains the previous instantiation of the layout class.

Upvotes: 1

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