Python For Loops - Enumerate

Question

can you help me with this? Tried the below code but doesn't work. I'm trying to print out the attached output. Thanks in advance.

num_display = int(input('Please enter how many numbers you would like displayed: '))
inc_value = int(input('Please enter the increment value: '))
num_counter = 1
num_sequence = range(1, num_display + 1 , inc_value)
value_counter = range(1, num_counter, inc_value)

for each_num in num_sequence:
    print(f'Counter: {num_counter} value: {each_num}')
    num_counter = num_counter + 1
    value_counter = value_counter + 1
print("Bye.")

What the output should look like

Please enter how many numbers you would like displayed: 12
Please enter the increment value: 3
Counter: 1 value: 1
Counter: 2 value: 4
Counter: 3 value: 7
Counter: 4 value: 10
Counter: 5 value: 13
Counter: 6 value: 16
Counter: 7 value: 19
Counter: 8 value: 22
Counter: 9 value: 25
Counter: 10 value: 28
Counter: 11 value: 31
Counter: 12 value: 34
Bye.

I made changes to the code to meet other conditions but I'm getting this error after converting str to int: line 11, in num_sequence = range(1,stop_value,inc_value) TypeError: 'str' object cannot be interpreted as an integer

my code:

num_display = input('Please enter how many numbers you would like displayed: ').strip()
inc_value = input('Please enter the increment value: ').strip()
zero_value = 0

if num_display.isdigit() and inc_value.isdigit():
    if int(num_display) != zero_value or int(inc_value) != zero_value:
        stop_value = int(num_display) * int(inc_value)
        num_sequence = range(1,stop_value,inc_value)
        for num_counter, each_num in enumerate(num_sequence):
                        print(f'Counter: {num_counter + 1} value: {each_num}')
        print('Bye.')
    else:
        print("I can't increment in steps of 0.")     

else:
    print('Positive non zero integers only please.')

I got it working using the below but it doesn't print the other one correctly, see screenshot:

num_display = input('Please enter how many numbers you would like displayed: ').strip()
inc_value = input('Please enter the increment value: ').strip()
zero_value = 0

if num_display.isdigit() and inc_value.isdigit():
    if int(num_display) != zero_value and int(inc_value) != zero_value:
        stop_value = int(num_display) * int(inc_value)
        num_sequence = range(1, int(stop_value), int(inc_value))
        for num_counter, each_num in enumerate(num_sequence):
                        print(f'Counter: {num_counter + 1} value: {each_num}')
        print('Bye.')
    else:
        print("I can't increment in steps of 0.")     

else:
    print('Positive non zero integers only please.')

working but not printing 5 on the other test

Answer 1

There are a few problems with your code. range() does increment the counter by inc_value automatically after each iteration, so don't manually update that counter in your loop.

Additionally there is a mathematical problem. If you want to print a number num_display times incremented by inc_value the formula to calculate the the last number (and hence the end value for range()) is start_value + inc_value * num_display, not num_display + 1. In your case the start_value is 1.

To get the number of iterations in a pythonic way use enumerate().

num_display = int(input('Please enter how many numbers you would like displayed: '))
inc_value = int(input('Please enter the increment value: '))
start_value = 1
num_sequence = range(1, start_value + num_display * inc_value, inc_value)

for num_counter, each_num in enumerate(num_sequence):
    print(f'Counter: {num_counter + 1} value: {each_num}')
print("Bye.")

Expected output

Please enter how many numbers you would like displayed: 12
Please enter the increment value: 3
Counter: 1 value: 1
Counter: 2 value: 4
Counter: 3 value: 7
Counter: 4 value: 10
Counter: 5 value: 13
Counter: 6 value: 16
Counter: 7 value: 19
Counter: 8 value: 22
Counter: 9 value: 25
Counter: 10 value: 28
Counter: 11 value: 31
Counter: 12 value: 34
Bye.