CODEWITHSUNDEEP
pythonwindowsnetwork-programming
BrickByBrick
BrickByBrick

Reputation: 1281

Using Python, how can I access a shared folder on windows network?

I have a file that I would like to copy from a shared folder which is in a shared folder on a different system, but on the same network. How can I access the folder/file? The usual open() method does not seem to work?

Upvotes: 87

Views: 285893

Answers (5)

Romojo
Romojo

Reputation: 91

Slight twist on the other answers: I was testing and needed to check if a remote file existed or not. I found this code did the trick

try:  
    #  
    f = open(r'\\<server name>\<folder>\<filename>')  
    print("found file")  
    f.close()  
except:  
    print("file not seen")

That 'close' is always a good idea (certainly in my case, where all I'm doing is checking presence).

Upvotes: 0

Andrew Peters
Andrew Peters

Reputation: 143

I had the same issue as OP but none of the current answers solved my issue so to add a slightly different answer that did work for me:

Running Python 3.6.5 on a Windows Machine, I used the format

r"\\DriveName\then\file\path\txt.md"

so the combination of double backslashes from reading @Johnsyweb UNC link and adding the r in front as recommended solved my similar to OP's issue.

Upvotes: 10

Chowdhury
Chowdhury

Reputation: 91

My remote server is on Linux Machine and the client on Windows. For me:

  1. glob.glob('//HOST/share/path/to/file') works with forward slash
  2. open(r'\\HOST\share\path\to\file') and open('\\\\HOST\\share\\path\\to\\file') worked with backward slash
  3. For pd.read_csv(), forward or backward slash, doesn't matter.

Upvotes: 1

johnsyweb
johnsyweb

Reputation: 141780

Use forward slashes to specify the UNC Path:

open('//HOST/share/path/to/file')

(if your Python client code is also running under Windows)

Upvotes: 133

glglgl
glglgl

Reputation: 91017

How did you try it? Maybe you are working with \ and omit proper escaping.

Instead of

open('\\HOST\share\path\to\file')

use either Johnsyweb's solution with the /s, or try one of

open(r'\\HOST\share\path\to\file')

or

open('\\\\HOST\\share\\path\\to\\file')

.

Upvotes: 48

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