CODEWITHSUNDEEP
pythongoogle-drive-api
Birdy
Birdy

Reputation: 13

Search a folder using ID via Google Drive API in python

I am using the Google Drive's API to create and search files and folders using python 3. Searching a folder is done using the files.list method of the drive API. Each search requires a query q as an input. Some examples of queries are given here. I can successfully search for a folder named hello using its name as given below:

service.files().list(q="name = 'hello'", pageSize=10, fields=files(id, name)).execute()

Now, let us say the ID of the folder is 123, then how can I search for this folder using the ID instead of the name. I have tried replacing q with id = '123' as well as id = 123 but none of it seems to work. The closest query I was able to find here was:

q = "'123' in parents"

But this will return all the files whose parent folder is the folder we are looking for.

Is there any way in which we can directly search folders or files by their ID?

Thank you.

Upvotes: 1

Views: 2419

Answers (1)

Tanaike
Tanaike

Reputation: 201378

I believe your goal is as follows.

  • You want to retrieve the folder metadata by the folder ID Drive API with googleapis for python.

In this case, how about the following sample script?

folderId = "###" # Please set the folder ID.
res = service.files().get(fileId=folderId, fields="id, name").execute()
  • In this case, "Files: get" method is used.

Additional information:

  • If you want to retrieve the folder list just under the specific folder, you can use the following modified search query.

      q = "'123' in parents and mimeType='application/vnd.google-apps.folder'"
    • In this case, 123 is the top folder ID.
    • In this modification, the retrieved mimeType is given. By this, only the folder list can be retrieved.

  • If you want to retrieve the file list except for the folder, you can also use the following search query.

      q = "'123' in parents and not mimeType='application/vnd.google-apps.folder'"

  • If you want to retrieve the folder ID from the folder name, you can use the following sample script. In this case, when there are same folder names of hello, those folders are returned.

      res = service.files().list(q="name = 'hello' and mimeType='application/vnd.google-apps.folder'", pageSize=10, fields="files(id, name)").execute()

Note:

  • In your showing script, please modify fields=files(id, name) of service.files().list(q="name = 'hello'", pageSize=10, fields=files(id, name)).execute() to fields="files(id, name)".

References:

Upvotes: 1

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