Reputation: 216
Assuming we have a sorted descending vector, like:
vector<int> array {26, 21, 13, 11, 8, 3, 2}.
I would like to insert a new and different element to the ones already present, so that descending sort of vector is kept.
Example flow:
A fast sample implementation in C++ would be:
#include<iostream>
#include<vector>
#include <chrono>
using namespace std;
using namespace std::chrono;
int get_Index_Insert(const vector<int>& array, int lengthArray, int insertValue)
{
int whereInsert = lengthArray;
for (int i = 0; i < lengthArray; i++)
{
if (array[i] < insertValue)
{
whereInsert = i;
break;
}
}
return whereInsert;
}
int get_Index_Insert2(const vector<int>& array, int lengthArray, int insertValue)
{
int whereInsert = lengthArray;
// Break out early if these cases:
if (lengthArray == 0 || (array[lengthArray - 1] > insertValue))
return whereInsert;
// Otherwise do your binary magic:
int low = 0;
int high = lengthArray - 1;
while (low <= high)
{
int mid = low + (high - low) / 2;
if (array[mid] > insertValue)
{
low = mid + 1;
}
else
{
high = mid - 1;
}
}
whereInsert = high + 1;
return whereInsert;
}
vector<int> insert_Value(const vector<int>& arrayInput, int insertValue)
{
vector<int> arrayOutput;
int lenghtArray = arrayInput.size();
// At what index to add?
int whereInsert = get_Index_Insert(arrayInput, lenghtArray, insertValue);
// Add it now:
for (int i = 0; i < whereInsert; i++)
arrayOutput.push_back(arrayInput[i]);
arrayOutput.push_back(insertValue);
for (int i = whereInsert + 1; i < lenghtArray + 1; i++)
arrayOutput.push_back(arrayInput[i - 1]);
return arrayOutput;
}
vector<int> insert_Value2(const vector<int>& arrayInput, int insertValue)
{
vector<int> arrayOutput;
int lenghtArray = arrayInput.size();
// At what index to add?
int whereInsert = get_Index_Insert2(arrayInput, lenghtArray, insertValue);
// Add it now:
for (int i = 0; i < whereInsert; i++)
arrayOutput.push_back(arrayInput[i]);
arrayOutput.push_back(insertValue);
for (int i = whereInsert + 1; i < lenghtArray + 1; i++)
arrayOutput.push_back(arrayInput[i - 1]);
return arrayOutput;
}
int main()
{
{
// START TIME
auto start = high_resolution_clock::now();
vector<int> array{ 26, 21, 13, 11, 8, 3, 2 };
array = insert_Value(array, 22);
array = insert_Value(array, 17);
array = insert_Value(array, 1);
array = insert_Value(array, 43);
auto stop = high_resolution_clock::now();
// END TIME
// Show time:
auto duration = duration_cast<microseconds>(stop - start);
cout << "Time taken by function 1, linear search: " << duration.count() << " microseconds" << endl;
for (int i = 0; i < array.size(); i++)
cout << array[i] << " ";
cout << endl;
}
{
// START TIME
auto start = high_resolution_clock::now();
vector<int> array{ 26, 21, 13, 11, 8, 3, 2 };
array = insert_Value2(array, 22);
array = insert_Value2(array, 17);
array = insert_Value2(array, 1);
array = insert_Value2(array, 43);
auto stop = high_resolution_clock::now();
// END TIME
// Show time:
auto duration = duration_cast<microseconds>(stop - start);
cout << "Time taken by function 2, binary search: " << duration.count() << " microseconds" << endl;
for (int i = 0; i < array.size(); i++)
cout << array[i] << " ";
cout << endl;
}
cout << endl << endl << endl;
return 0;
}
Other info that may help in deciding recommended method:
Is there any way better to do it than above? in less complexity involved? Any source material I may have missed and that might help is very much appreciated also.
EDIT: After some more investigations and using binary search method while seeking index position for actual element insertion (thanks to the debates from comments), edited my above sample a bit, testing execution time of a "get_Index_Insert2(...) function using early returns and binary search.
Times received (microseconds), after 3 runs:
Time taken by function 1, linear search: 60 microseconds
43 26 22 21 17 13 11 8 3 2 1
Time taken by function 2, binary search: 33 microseconds
43 26 22 21 17 13 11 8 3 2 1
Time taken by function 1, linear search: 61 microseconds
43 26 22 21 17 13 11 8 3 2 1
Time taken by function 2, binary search: 34 microseconds
43 26 22 21 17 13 11 8 3 2 1
Time taken by function 1, linear search: 61 microseconds
43 26 22 21 17 13 11 8 3 2 1
Time taken by function 2, binary search: 34 microseconds
43 26 22 21 17 13 11 8 3 2 1
Upvotes: 1
Views: 849
Reputation: 6805
You don't need to pass the size of the vector, std::vector
already have a member function size()
.
I think you overcomplicated things. You just have to iterate over the vector and compare each element with the value you want to insert. If the comparison evaluates to false
, then you found where to insert the new element.
You may implement the function the following way:
template <typename val_t, typename Compare>
void insert_ordered(std::vector<val_t> & vec, const val_t & val, Compare comp)
{
bool inserted(false);
for(typename std::vector<val_t>::iterator it = vec.begin(); !inserted && (it != vec.end()); ++it)
{
if(!comp(*it, val))
{
vec.insert(it, val);
inserted = true;
}
}
if(!inserted)
vec.push_back(val);
}
It takes the vector, the value to instert and the comparison function you want.
For your use case, it may be used like this:
int main()
{
std::vector<int> v {26, 21, 13, 11, 8, 3, 2};
insert_ordered(v, 22, std::greater<int>());
insert_ordered(v, 17, std::greater<int>());
insert_ordered(v, 1, std::greater<int>());
insert_ordered(v, 43, std::greater<int>());
for(const int & i : v)
std::cout << i << ' ';
return 0;
}
Output:
43 26 22 21 17 13 11 8 3 2 1
If, for some reason, you can't use std::greater
, you can define your own comparator like this:
auto desc_comp = [](const int & lhs, const int & rhs)
{
return lhs > rhs;
};
And use it like this:
insert_ordered(v, 22, desc_comp);
Edit:
If you don't mind having several exit points in the function, it can be simplified as:
template <typename val_t, typename Compare>
void insert_ordered(std::vector<val_t> & vec, const val_t & val, Compare comp)
{
for(typename std::vector<val_t>::iterator it = vec.begin(); it != vec.end(); ++it)
{
if(!comp(*it, val))
{
vec.insert(it, val);
return;
}
}
vec.push_back(val);
}
Upvotes: 1
Reputation: 253
#include <algorithm>
#include<iostream>
#include<vector>
using namespace std;
std::vector<int>::const_iterator get_Index_Insert(const vector<int>& array ,int insertValue) {
return std::find_if(array.cbegin(),array.cend(),[insertValue](int aValue) { return aValue < insertValue;});
}
void insert_Value(vector<int>& arrayInput, int insertValue, std::vector<int>::const_iterator aIt)
{
arrayInput.insert(aIt,insertValue);
}
int main()
{
vector<int> array{26, 21, 13, 11, 8, 3, 2 };
auto myIt = get_Index_Insert(array,22);
insert_Value(array,22,myIt);
for (int i = 0; i < array.size(); i++)
cout << array[i] << " ";
cout << endl << endl << endl;
return 0;
}
This is only an idea, then it can be enhanced
Upvotes: 1
Reputation: 2140
Instead of creating a new vector
you can use the insert
function to put the new value into the existing list at the desired index. See https://en.cppreference.com/w/cpp/container/vector/insert
void insert_Value(const vector<int>& arrayInput, int insertValue)
{
int lenghtArray = arrayInput.size();
// At what index to add?
int whereInsert = get_Index_Insert(arrayInput, lenghtArray, insertValue);
arrayInput.insert(whereInsert, insertValue);
}
Upvotes: 1