CODEWITHSUNDEEP
python
user18733201
user18733201

Reputation:

Finding the minimum result of a list of results

Is there a code to define / sort through lists?

Upvotes: 0

Views: 128

Answers (2)

preritdas
preritdas

Reputation: 515

A quick and straightforward solution would be to create a list of results and then corroborate the index with your list of remaining points (because they are inherently lined up). Below is a step-by-step process to achieving this, and at the very bottom is a cleaned-up version of the code.

def find_closest(start_point, remaining_points):
    results = []  # list of results for later use
    for element in list(remaining_points):
        result = distance(start_point, element)
        results.append(result)  # append the result to the list

    # After iteration is finished, find the lowest result
    lowest_result = min(results)
    # Find the index of the lowest result
    lowest_result_index = results.index(lowest_result)
    # Corroborate this with the inputs
    closest_point = remaining_points[lowest_result_index]
    # Return the closest point
    return closest_point

Or to simplify the code:

def find_closest(start_point, remaining_points):
    results = []
    for element in remaining_points:
        results.append(distance(start_point, element))
    
    return remaining_points[results.index(min(results))]

Edit: you commented saying you can't use Python's in-built min() function. A solution would be to just create your own functional minimum_value() function.

def minimum_value(lst: list):
    min_val = lst[0]
    for item in lst:
        if item < min_val:
            min_val = item
    return min_val

def find_closest(start_point, remaining_points):
    results = []
    for element in remaining_points:
        results.append(distance(start_point, element))
    
    return remaining_points[results.index(minimum_value(results))]

Upvotes: 0

Raida
Raida

Reputation: 1506

Advanced solution

You can use the min function of python with the key argument like this:

def find_closest(start_point, remaining_points):
    return min(remaining_points, key=lambda a: distance(start_point, a))

Basic solution

Because of your specific needs (only loops and if statements), here is another solution. For other people who are not restricted, I recommend using the above solution.

def find_closest(start_point, remaining_points):
    closest = None
    closest_distance = 1000000
    # Better but more advanced initialisation
    # closest_distance = float("inf")
    for element in list(remaining_points):
        dist = distance(start_point, element)
        if dist < closest_distance:
            closest = element
            closest_distance = dist
    return closest

Explanation

Before going through all points, we initialise the closest point to None (it is not found yet) and the closest_distante to a very high value (to be sure that the first evaluated point will be closer).

Then, for each point in remaining_points, we calculate its distance from start_point and store it in dist.

If this distance dist is less than closest_distance, then the current point is closest from the current stored one, so we update the stored closest point closest with the current point and we update the closest_distance with the current distance dist.

When all points have been evaluated, we return the closest point closest.

Links for more information

Upvotes: 6

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