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javamethods
David Hofmann
David Hofmann

Reputation: 5775

How does Java method reference String::compareTo implementing Comparator<String> works?

java.util.Comparator<String> lambda = (s1, s2) -> s1.compareTo(s2); // line 1
java.util.Comparator<String> methodRef = String::compareTo;         // line 2

I can't understand why line 2 works without error, and why it is equivalent to line 1. Line 2 is returning a method reference that receives a string and returns and int (i.e. int compare(String s) ), however, comparator functional method signature is int compare(T o1, T o2);

Upvotes: 1

Views: 264

Answers (1)

Arturo Volpe
Arturo Volpe

Reputation: 3627

The ref to String::compareTo is a special kind of method reference called "Reference to an Instance Method of an Arbitrary Object of a Particular Type".

In this case, the compiler knows that we are referencing a not-static method of a given class, and it can translate to a functional interface with the desired signature.

For example:

String t1 = "t1";
String t2 = "t2";

// this
Comparator<String> comparator = String::compareTo;
comparator.compareTo(t1, t2);

// will be 'translated' to:
Comparator<String> comparator = (String s1, String s2) -> s1.compareTo(s2);
t1.compareTo(t2);

Note that the method will be called with the context of the first parameter (the this used will be t1).

Points 8 and 9 of State of lambda give a rationale for this implementation.

From Overview of method references youtube video

Overview of method references

Upvotes: 5

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