Reputation: 95
I'm writing my codefixer with roslyn. I want it to work in such way:
Before:
IEnumerable<int> list = new List<int> {1, 2, 3, 4};
list = list.Where(x => x%2 == 0);
After:
...
IEnumerable<int> list = new List<int> {1, 2, 3, 4};
list = list.Where(lambdaMethod);
...
private static bool lamdaMethod(int x)
{
return x % 2 == 0;
}
The problem is that I can't find the proper way to get return type for the method and type of argument.
My method from analyzer template:
public sealed override async Task RegisterCodeFixesAsync(CodeFixContext context)
{
var root = await context.Document.GetSyntaxRootAsync(context.CancellationToken).ConfigureAwait(false);
// TODO: Replace the following code with your own analysis, generating a CodeAction for each fix to suggest
var diagnostic = context.Diagnostics.FirstOrDefault();
var diagnosticSpan = diagnostic.Location.SourceSpan;
// Find the type declaration identified by the diagnostic.
var declaration = root.FindToken(diagnosticSpan.Start).Parent.AncestorsAndSelf()
.OfType<LambdaExpressionSyntax>().FirstOrDefault();
if (declaration == null)
return;
// Register a code action that will invoke the fix.
context.RegisterCodeFix(
CodeAction.Create(
title: $"{"Just Title"}",
createChangedDocument: c => MakeLambdaOptimization(context.Document, declaration, c),
equivalenceKey: nameof(CodeFixResources.CodeFixTitle)),
diagnostic);
}
As you see, I'm working with LambdaExpressionSyntax
. There are also SimpleLambdaExpressionSyntax
and ParenthesizedLambdaExpressionSyntax
which help me to get ParameterSyntax
. In the ParameterSyntax
I can find Type
, but it's null and I get NullReferenceException.
I tried to get the whole type of lambda (e.g. Func<int, bool>
), I guess it would help me. How can I do it? I've heard about SemanticModel, but I don't know how to use it
Upvotes: 2
Views: 449
Reputation: 4944
You can use SemanticModel.GetSymbolInfo(ExpressionSyntax)
to get the lambda symbol. From the lambda symbol you can find the information you need (return type and parameter types). Here is a code snippet (written in the context of a Console Application instead of a codefix for simplicity - you'll be able to get it working for codefixes):
using Microsoft.CodeAnalysis;
using Microsoft.CodeAnalysis.CSharp;
using Microsoft.CodeAnalysis.CSharp.Syntax;
// You don't need to create or get a compilation yourself. I'm creating it manually since I'm in a console app.
CSharpCompilation comp = CSharpCompilation.Create(null, new[] { SyntaxFactory.ParseSyntaxTree("System.Func<int, bool> f = x => x % 2 == 0;") }, new[] { MetadataReference.CreateFromFile(typeof(Func<>).Assembly.Location) });
// You already have the LambdaExpressionSyntax, ignore the following two lines, which again because I'm in a console app.
var root = comp.SyntaxTrees[0].GetRoot();
var lambda = root.DescendantNodes().OfType<LambdaExpressionSyntax>().Single();
// Here you'll need to get a semantic model via 'await context.Document.GetSemanticModelAsync(context.CancellationToken).ConfigureAwait(false);'
var model = comp.GetSemanticModel(lambda.SyntaxTree);
// That's the core of what you want to do.
if (model.GetSymbolInfo(lambda).Symbol is IMethodSymbol lambdaSymbol)
{
// prints 'bool'
Console.WriteLine(lambdaSymbol.ReturnType.ToDisplayString());
foreach (var parameter in lambdaSymbol.Parameters)
{
// prints 'int' (loop is entered once since my lambda has a single parameter).
Console.WriteLine(parameter.Type.ToDisplayString());
}
}
Upvotes: 2