CODEWITHSUNDEEP
javascriptnode.jsmongodbexpressmongoose
Alberto Enríquez
Alberto Enríquez

Reputation: 135

Mongoose query always returns empty array

Im trying to make a greater than query but it always returns an empty array.

    const productSchema = require("./productsSchema");
const getProductsGreaterThan = async (minimum_id) => {
try{
    console.log(minimum_id);
    const productById = await productSchema.find({id: {$gt:minimum_id}});
    return productById
}
catch(err){
    console.error(err);
}
}

This is my controller:

if (req.params.minimum_id) {
    const productsById = await productsModel.getProductsGreaterThan(req.params.minimum_id);
    res.status(200).json(productsById);
}

It should return the products with an ID greater than what i type in the req.params...

routes.get("/products/:minimum_id?",productRoutes.getProductsGreaterThan);

But when i write the route like this in the url it gives me an empty array => http://localhost:3000/products/10 What is wrong with this code? Im very confused, because other queries like find({}) work. My mongoose version is 6.2.10.

Upvotes: 0

Views: 947

Answers (3)

Quzu
Quzu

Reputation: 21

I solved my issue by changing MongoDB table name. The problem was in the name of the collection of mongoDB. Your table names should be always in lower-case and plural (this was most critical thing in my case). Maybe you can try this.

Upvotes: 2

Alberto Enríquez
Alberto Enríquez

Reputation: 135

Solved. Somehow the problem was in the name of the collection of mongoDB. It seems it should be always in lower-case and plural.

Upvotes: 3

Dylan L.
Dylan L.

Reputation: 1317

If you are using mongoose and MongoDB the correct id format is _id. So you would do the following:

productSchema.find({_id: {$gt:minimum_id}})

Upvotes: 1

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