Reputation: 7162
I have an array of data classes I need to serialize to JSON. I wrap the list in a class (Persons
)
@attrs.frozen
class Person:
name: str
age: int
grades: Dict[str, int]
@attrs.define
class Persons:
persons: List[Person] = attrs.field(factory=list)
def add(self, person: Person) -> None:
self.persons.append(person)
def run(filename: str) -> None:
college = Persons()
college.add(Person("uzi" , 51, {"math": 100, "cs": 90}))
college.add(Person("dave", 76, {"math": 94, "music": 92}))
college.add(Person("dan", 22, {"bible": 98}))
with open(filename, "w+") as fl:
fl.write(f"{json.dumps(attrs.asdict(college), indent=4)}\n")
Can I somehow get rid of the wrapping class and still serialize a List[Person]
easily?
Upvotes: 2
Views: 2018
Reputation: 11662
For a high level approach with dataclasses
, I recommend checking out the dataclass-wizard
library.
It provides a few generic and useful implementations, such as a Container type, which is just a convenience wrapper around a list
type in Python.
It also exposes useful mixin classes which make it easier to work with YAML/JSON files, as shown below.
from dataclasses import dataclass
from dataclass_wizard import Container, JSONListWizard, JSONFileWizard
# optional: extend from `JSONListWizard`, so de-serializing a list results
# in a `Container` object; though you could also use `JSONWizard` instead.
# also extend from `JSONFileWizard`, so we can de-serialize data back from
# a JSON file.
@dataclass(frozen=True)
class Person(JSONListWizard, JSONFileWizard):
name: str
age: int
grades: dict[str, int]
def run(filename: str) -> None:
# create a `Container` object, which is just a wrapper around a Python `list`
college = Container[Person]()
college.append(Person("uzi", 51, {"math": 100, "cs": 90}))
college.append(Person("dave", 76, {"math": 94, "music": 92}))
college.append(Person("dan", 22, {"bible": 98}))
# serialize the list of instances to a json file
college.to_json_file(filename, indent=4)
run('my_file.json')
# now, read it back :-)
people = Person.from_json_file('my_file.json')
The contents of my_file.json
would look like:
[
{
"name": "uzi",
"age": 51,
"grades": {
"math": 100,
"cs": 90
}
},
{
"name": "dave",
"age": 76,
"grades": {
"math": 94,
"music": 92
}
},
{
"name": "dan",
"age": 22,
"grades": {
"bible": 98
}
}
]
Upvotes: 0
Reputation: 7113
You can use default
argument of the json.dumps
function and pass the function attrs.asdict
to serialize it.
I have added the "persons" key so it matches the output of your code.
import json
import attrs
@attrs.frozen
class Person:
name: str
age: int
grades: dict[str, int]
def run(filename: str) -> None:
college = []
college.append(Person("uzi", 51, {"math": 100, "cs": 90}))
college.append(Person("dave", 76, {"math": 94, "music": 92}))
college.append(Person("dan", 22, {"bible": 98}))
with open(filename, "w+") as fl:
fl.write(
f"{json.dumps({'persons': college}, default=attrs.asdict, indent=4)}\n"
)
run("my_json.json")
Output
{
"persons": [
{
"name": "uzi",
"age": 51,
"grades": {
"math": 100,
"cs": 90
}
},
{
"name": "dave",
"age": 76,
"grades": {
"math": 94,
"music": 92
}
},
{
"name": "dan",
"age": 22,
"grades": {
"bible": 98
}
}
]
}
Upvotes: 3