Reputation: 37
I have a collection of documents that looks like this
{
"_id": "4",
"contacts": [
{
"email": "[email protected]",
"name": "A1",
"phone": "00",
"crashNotificationEnabled": false,
"locationShared": true,
"creationDate": ISODate("2020-10-19T15:19:04.498Z")
},
{
"email": "[email protected]",
"name": "AG2",
"phone": "00",
"crashNotificationEnabled": false,
"locationShared": false,
"creationDate": ISODate("2020-10-19T15:19:04.498Z")
}
],
"creationDate": ISODate("2020-10-19T15:19:04.498Z"),
"_class": ".model.UserContacts"
}
And i would like to iterate through all documents to check if either crashNotificationEnabled
or locationShared
is true and add +1 to a counter if its the case, im quite new to python and mongosql so i actually have a hard time trying to do that, i tried a lot of things but there is my last try :
def users_with_guardian_angel(mongoclient):
try:
mydb = mongoclient["main"]
userContacts = mydb["userContacts"]
users = userContacts.find()
for user in users:
result = userContacts.find_one({contacts : { $in: [true]}})
if result:
count_users = count_users + 1
print(f"{count_users} have at least one notificiation enabled")
But the result variable stays empty all the time, so if somebody could help me to accomplish what i want to do and tell what i did wrong here ?
Thanks !
Upvotes: 0
Views: 367
Reputation: 11942
Here's one way you could do it by letting the MongoDB server do all the work.
N.B.: This doesn't consider the possibility of multiple entries of the same user.
db.userContacts.aggregate([
{
"$unwind": "$contacts"
},
{
"$match": {
"$expr": {
"$or": [
"$contacts.crashNotificationEnabled",
"$contacts.locationShared"
]
}
}
},
{
"$count": "userCountWithNotificationsEnabled"
}
])
Try it on mongoplayground.net.
Example output:
[
{
"userCountWithNotificationsEnabled": 436
}
]
Upvotes: 1