CODEWITHSUNDEEP
ruby-on-railsruby
NullVoxPopuli
NullVoxPopuli

Reputation: 65143

Ruby: more efficient way to convert table_name into object Model?

So.. I'm trying to do something like this:

"active_record_object" => ActiveRecordObject

with the following code:

ar_object = (object.singularize.split("_").each{|o| o.capitalize!}).join.constantize #convert to ActiveRecord object

is there a more efficient way to do this? chaining 7 string manipulation methods together seems a lil crazy for ruby.

Upvotes: 3

Views: 62

Answers (1)

Michael Kohl
Michael Kohl

Reputation: 66837

There's a method called classify for that:

"active_record_object".classify
 # => "ActiveRecordObject"

Edit: as pointed out in the comments, "active_record_object".classify.constantize gets you all the way.

Upvotes: 5

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