Reputation:
I'm working with GWAS data, My data looks like this:
IID,kgp11004425,rs11274005,kgp183005,rs746410036,kgp7979600
1,00,AG,GT,AK,00
32,AG,GG,AA,00,AT
300,TT,AA,00,AG,AA
400,GG,AG,00,GT,GG
Desired Output:
IID,kgp11004425,rs11274005,kgp183005,rs746410036,kgp7979600
1,N/A,AG,GT,AK,N/A
32,AG,GG,AA,N/A,AT
98,TT,AA,N/A,AG,AA
3,GG,AG,N/A,GT,GG
Here I'm trying to replace "00" with "N/A", but since I have 00 in the first_row/header_row and First column i.e IId, it's replacing here with N/A like kgp11N/A4425, rs11274N/A5,kgp183N/A5.... and Id column values with 300, 400, 500 as 3N/A, 4N/A, 5N/A. The bash command I used:
sed 's~00~N/A~g' allSNIPsFinaldata.csv
Can anyone please help "how not to include/Skip the first row or header row and first column and apply this effect. please help
Upvotes: 1
Views: 153
Reputation: 163642
You might also skip the first row starting from the second one:
sed '2,$s~00~N/A~g' allSNIPsFinaldata.csv
If you don't want partial word matches, you can implement word boundaries around the 00
in different ways.
Upvotes: 0
Reputation: 81
You may specify an address to select the line(s) to apply the command to. Thus you might choose to exclude the first line like this:
sed '1!s~00~N/A~g' allSNIPsFinaldata.csv
As a sidenote I'd like to note that your example isn't actually CSV despite the file name; your header is comma-delimited but the rest of the file is using spaces.
Upvotes: 1
Reputation: 786359
With 2 capture groups you can use this sed
:
sed -E 's~(^|[[:blank:]])00([[:blank:]]|$)~\1N/A\2~g' file
IID, kgp11004425, rs11274005, kgp183005, rs746410036, kgp7979600
1 N/A AG GT AK N/A
32 AG GG AA N/A AT
98 TT AA N/A AG AA
3 GG AG N/A GT GG
Details:
(^|[[:blank:]])
: Match start or a whitespace in capture group #100
: Match 00
([[:blank:]]|$)
: Match end or a whitespace in capture group #2\1N/A\2
: Replacement to put back value of capture group #1 followed by N/A
followed by value of capture group #2Upvotes: 2