CODEWITHSUNDEEP
pythonsignalspython-3.6
Rahul.In
Rahul.In

Reputation: 73

CTLR + C interrupt signal in python causes raise KeyboardInterrupt("Execution interrupted")

I have the following code running on Python 3.9.0 on a windows 10 machine.

Plan is to exit from the while loop and exit gracefully,It should print some message here 'hello'and exit.

import signal # Import signal module using the import keyword
import time

# available signalson our System
valid_signals = signal.valid_signals() #requires python3.9.0
print(valid_signals)

#create a Signal Handler
def SignalHandler(SignalNumber,Frame):
    print('hello')
    print(f'Signal Number -> {SignalNumber} Frame -> {Frame} ')
    
signal.signal(signal.SIGINT,SignalHandler)

while 1:  
    print("Press Ctrl + C") 
    time.sleep(1)

When i run this, I am getting this KeyboardInterrupt: Execution interrupted strong text here is the output of the script

Python 3.9.0 (C:\Python\python.exe)
>>> %Run Python-.py
{<Signals.SIGINT: 2>, <Signals.SIGILL: 4>, <Signals.SIGFPE: 8>, <Signals.SIGSEGV: 11>, <Signals.SIGTERM: 15>, <Signals.SIGBREAK: 21>, <Signals.SIGABRT: 22>}
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Press Ctrl + C
Traceback (most recent call last):
  File "E:\_1_Personal\MY PROJECTS\SourceCodes\Python3-Tutorial\Python-.py", line 18, in <module>
    time.sleep(1)
  File "C:\Thonny\lib\site-packages\thonny\backend.py", line 346, in signal_handler
    raise KeyboardInterrupt("Execution interrupted")
KeyboardInterrupt: Execution interrupted
>>>

Why is the code not going to the Signal handler and printing hello?

Upvotes: 1

Views: 778

Answers (2)

Rahul.In
Rahul.In

Reputation: 73

Issue was with the IDE ,Thonny and IDLE When i tried running the code on command line directly,

C:> python Abovepythoncode.py

No issues were found

Upvotes: 1

Dmiich
Dmiich

Reputation: 375

try this and put your code in try block, And when you press CTRL + C then exception will occure

try:
    # main code here
except KeyboardInterrupt:
    print ('KeyboardInterrupt exception is caught')
else:
    print ('No exceptions are caught')

Upvotes: 0

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