Reputation: 493
I want to debug both workout.js and test.js but vscode is debugging only the workout.js how do I set the file name dynamic. so I can debug any js file with one launch.json config
Like
"program": "${workspaceFolder}/${currentFileName}.js",
Upvotes: 1
Views: 858
Reputation: 493
Refer to the documentation for details.
{
"version": "0.2.0",
"configurations": [
{
"name": "Node js",
"program": "${file}",
"request": "launch",
"skipFiles": ["<node_internals>/**"],
"type": "node"
}
]
}
Upvotes: 1
Reputation: 192
The easy way is to add multiple settings inside your single lunch config file. and whenever you want to debug any then choose that name while debugging
Upvotes: 0
Reputation: 554
Take a look at the official documentation about variable substitution in Debugging and Task configuration files, there are a few that can be used to achieve what you want.
Upvotes: 0