CODEWITHSUNDEEP
python
Johnnyduke
Johnnyduke

Reputation: 29

How do you create a list of lists using a 'for' loop with input(s)

I'm trying to create lists/ records using the input function and 'for' loops, but I can't seem to get more than one list to populate. Ideally, I like to be able to define the number of sub-lists I want to create and then input the information per list until the total number of specified lists has been created.

def new_row(n):
    for i in n:
        y = []
        month = input('Enter the month: ')
        city = input('Enter the city: ')
        numCoups = input('Enter the number of coupons accepted: ')
        numAds = input('Enter the number of advertisments ran: ')
        l = [month, city, numCoups, numAds]
        y.append(l)

new_row(input('How many entries do you wish to input'))

Upvotes: 0

Views: 115

Answers (4)

Punisher
Punisher

Reputation: 56

if n is a number you should change n to range(n) it's unclear n, also you have to let y grow by lefting it outside the loop because it will always be dscarded, finally you must return the value of y because if you don't do this you are also discarding it, maybe you can pass it as a parameter if you want to reuse it. For Example:

def new_row(n, y=[]):
    for i in range(n):
        month = input('Enter the month: ')
        city = input('Enter the city: ')
        numCoups = input('Enter the number of coupons accepted: ')
        numAds = input('Enter the number of advertisments ran: ')
        l = [month, city, numCoups, numAds]
        y.append(l)
    return y

result_rows=new_row(input('How many entries do you wish to input'))

Upvotes: -1

user18932371
user18932371

Reputation: 

def new_row(n):
    y=[] #outside the loop
    for i in range(n)#range function:
        month = input('Enter the month: ')
        city = input('Enter the city: ')
        numCoups = input('Enter the number of coupons accepted: ')
        numAds = input('Enter the number of advertisments ran: ')
        l = [month, city, numCoups, numAds]
        y.append(l)
    new_row(int(input('How many entries do you wish to input'))) #int function

You should declare the list outside the loop and you should convert the input to an integer, because by default it's a string,you should use range func in for loop

Upvotes: 2

kenntnisse
kenntnisse

Reputation: 427

def new_row(n):
    y = [] # outside the loop, otherwise it keeps on getting reset
    for i in range(n): # or [for i in range(int(n)):], if n is a string
        month = input('Enter the month: ')
        city = input('Enter the city: ')
        numCoups = input('Enter the number of coupons accepted: ')
        numAds = input('Enter the number of advertisments ran: ')
        l = [month, city, numCoups, numAds]
        y.append(l)

new_row(int(input('How many entries do you wish to input')))
        #you need to do int(input()) because input normally returns a string, but you want a number

Upvotes: 0

Nin17
Nin17

Reputation: 3472

You need to create the initial list outside the for loop and you need to convert the input to an integer and use range(n) instead of n:

def new_row(n):
    y = []
    for i in range(int(n)):
        month = input('Enter the month: ')
        city = input('Enter the city: ')
        numCoups = input('Enter the number of coupons accepted: ')
        numAds = input('Enter the number of advertisments ran: ')
        l = [month, city, numCoups, numAds]
        y.append(l)
    return y

new_row(input('How many entries do you wish to input'))

Upvotes: 0

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