CODEWITHSUNDEEP
pythonlist
user18175092
user18175092

Reputation:

Check that elements exist within a list Python

Is there a way to check that Elements within list1 are part of list2? What I've tried is down below... But I don't get an ouput. I'm guessing the 'in' function only deals with individual elements?

pattern=['Tacos', 'Pizza']
Foods=['Tacos', 'Pizza', 'Burgers', 'Fries', 'Ice-cream']

if pattern in foods:
    print('yes')

Upvotes: 0

Views: 89

Answers (4)

Sharim09
Sharim09

Reputation: 6214

Because pattern is a list but you want to check every element inside the pattern list then you need to use a loop.

pattern=['Tacos', 'Pizza']
Foods=['Tacos', 'Pizza', 'Burgers', 'Fries', 'Ice-cream']

for patt in pattern:
    if patt in foods:
        print('yes')

Upvotes: 0

Dieter
Dieter

Reputation: 2659

Substract foods from pattern and the list should be empty.

len( set(pattern) - set(Foods) ) == 0

or, intersection should be equal to the length of the pattern

len( set(pattern) & set(Foods) ) == len(pattern)

Upvotes: 0

Samwise
Samwise

Reputation: 71424

Using set logic:

>>> set(pattern).issubset(foods)
True

Using iteration over the lists (this is less efficient in general, especially if pattern is long, but it's useful to understand how this works where your original in check didn't):

>>> all(food in foods for food in pattern)
True

Upvotes: 0

theherk
theherk

Reputation: 7546

You can do it as a simple set logic.

set(pattern).issubset(foods)

Upvotes: 4

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