CODEWITHSUNDEEP
pythonplotlychoropleth
Greencolor
Greencolor

Reputation: 687

Adjust the size of the text label in Plotly

I'm trying to adjust the text size according to country size, so the text will be inside the boarders of the country. Here's my code:

# imports
import pandas as pd
import plotly.express as px

# uploading file
df=pd.read_csv('regional-be-daily-latest.csv', header = 1)

# creating figure
fig = px.choropleth(df, locations='Code', color='Track Name')
fig.update_layout(margin={"r":0,"t":0,"l":0,"b":0})

fig.add_scattergeo(

  locations = df['Code'],
  text = df['Track Name'],
  mode = 'text',
)

fig.show()

The output visualization that my code gives me is:

enter image description here

The text label for the orange country is inside the boarders of the country but the text to label the blue country is bigger than the country itself.

What I'm looking for would be to adjust the size so it will not exceed the boarders of the country. How can I do this?

Upvotes: 16

Views: 47570

Answers (2)

HR85
HR85

Reputation: 29

Text and Annotations in Python

You can Controll Text Size with uniformtext like this

fig.update_traces(textposition='inside')
fig.update_layout(uniformtext_minsize=8, uniformtext_mode='hide')

or Controll Maximum Text Size

fig.update_traces(textposition='inside', textfont_size=14)

These ways you don't change axis and label font sizes.

Upvotes: 2

Trishant Pahwa
Trishant Pahwa

Reputation: 2943

You can set the font size using the update_layout function and specifying the font's size by passing the dictionary in the font parameter.

import pandas as pd
import plotly.express as px

df=pd.read_csv('regional-be-daily-latest.csv', header = 1)

fig = px.choropleth(df, locations='Code', color='Track Name')
fig.update_layout(margin={"r":0,"t":0,"l":0,"b":0})

fig.add_scattergeo(

  locations = df['Code'],
  text = df['Track Name'],
  mode = 'text',
)


fig.update_layout(
    font=dict(
        family="Courier New, monospace",
        size=18,  # Set the font size here
        color="RebeccaPurple"
    )
)

fig.show()

Upvotes: 21

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