Reputation: 1
I'm not sure why I'm getting inf values when plugging in a 3 equation answer, another set of eyes on the equation loop would be useful, when I use a single equation the number of iterations is correct but when it's more than that the numbers multiply to inf.
Inputs for the code I used
Enter the Total Number of Equations: 3
Enter Allowed Error: 0.5
Enter the Co-Efficients
Matrix[1][1] = 1
Matrix[1][2] = 2
Matrix[1][3] = 3
Matrix[1][4] = 4
Matrix[2][1] = 2
Matrix[2][2] = 3
Matrix[2][3] = 4
Matrix[2][4] = 5
Matrix[3][1] = 3
Matrix[3][2] = 4
Matrix[3][3] = 5
Matrix[3][4] = 6
#include<stdio.h>
#include<math.h>
int main()
{
int count, t, limit;
float temp, error, a, sum = 0;
float matrix[10][10], y[10], allowed_error;
printf("\nEnter the Total Number of Equations:\t");
scanf("%d", &limit);
printf("Enter Allowed Error:\t");
scanf("%f", &allowed_error);
printf("\nEnter the Co-Efficients\n");
for(count = 1; count <= limit; count++)
{
for(t = 1; t <= limit + 1; t++)
{
printf("Matrix[%d][%d] = ", count, t);
scanf("%f", &matrix[count][t]);
}
}
for(count = 1; count <= limit; count++)
{
y[count] = 0;
}
do
{
a = 0;
for(count = 1; count <= limit; count++)
{
sum = 0;
for(t = 1; t <= limit; t++)
{
if(t != count)
{
sum = sum + matrix[count][t] * y[t];
}
}
temp = (matrix[count][limit + 1] - sum) / matrix[count][count];
error = fabs(y[count] - temp);
if(error > a)
{
a = error;
}
y[count] = temp;
printf("\nY[%d]=\t%f", count, y[count]);
}
printf("\n");
}
while(a >= allowed_error);
printf("\n\nSolution\n\n");
for(count = 1; count <= limit; count++)
{
printf("\nY[%d]:\t%f", count, y[count]);
}
return 0;
}
Upvotes: 0
Views: 123
Reputation: 20705
Your code is correct. The issue is that Gauss-Seidel method does not always converge. The convergence criteria is that the matrix A must be either:
The input matrix you used is neither symmetric, nor diagonally-dominant. Hence, the method fails to converge to a solution.
Upvotes: 2