CODEWITHSUNDEEP
pythonhtmlseleniumselenium-chromedriver
DiamondJoe12
DiamondJoe12

Reputation: 1809

Using Selenium to get image src inside of a link

I'm trying to get some info from this page using Selenium:

https://www.bandsintown.com/e/1024477910-hot-8-brass-band-at-the-howlin'-wolf?came_from=253&utm_medium=web&utm_source=city_page&utm_campaign=event

I want to get the src of the image on the right side of page.

enter image description here

Here's the page inspector - the src tag I'm trying to get is circled:

enter image description here

I need to access the src without referencing any explicit div names, so what I want to do is find the href instance which contains the image, and then search for the image inside of the a tag.

Here's my code, which fails to retrieve anything (printing find_src prints nothing) :

find_src = driver.find_element_by_css_selector('a[href^="https://www.bandsintown.com/a/"]//img').get_attribute("src")

What am I doing wrong here?

Upvotes: 0

Views: 353

Answers (1)

Rahul
Rahul

Reputation: 139

Please retry by replacing your css selector expression with this one: "a[href^='https://www.bandsintown.com/a/'] img". So, your rectified code will be:

find_src = driver.find_element_by_css_selector("a[href^='https://www.bandsintown.com/a/'] img").get_attribute("src")

If we want to select a descendant element using CSS selectors, space " " is used but in your CSS selector expression, "//" is there. For more information, kindly refer this link: https://developer.mozilla.org/en-US/docs/Web/CSS/CSS_Selectors

Upvotes: 1

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