CODEWITHSUNDEEP
phpjavascript
Darrell
Darrell

Reputation: 45

javascript capture and display php variable

I have standard text links which all say "Full View". When clicked these links send out php in this form: http://mysite.com/fullview.php?myimage=30

Basically there's thumbnailed images and text links that say full view. I'd like for fullview.php to capture the myimage variable, and display it as a full sized image. Meaning, a blank page (fullview.php) displaying the image. Sounds likes javascript to me.

How do you put the javascript into fullview.php to capture the variable and display it as a full sized image?

Thanks for any help, Darrell

Upvotes: 2

Views: 415

Answers (2)

sushil bharwani
sushil bharwani

Reputation: 30217

You just need to read the query parameters. In fullview.php you can use

$myimage = $_GET['myimage']; to capture this variable. And then can use it accordingly.

Upvotes: 1

i100
i100

Reputation: 4666

php is server side script javascript is client side script

so displaying a web page to a user first is executed php and result is send to client. After he receive it then javascript is executed

HTH

Ivo Stoykov

Upvotes: 1

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