CODEWITHSUNDEEP
bashsortinguniq
edddd
edddd

Reputation: 482

How to remove duplicate lines in a file?

I understand that the general approach is to use something like

$ sort file1.txt | uniq > file2.txt

But I was wondering if there was a way to do this without needing separate source and destination files, even if it means it can't be a one-liner.

Upvotes: 2

Views: 8638

Answers (4)

M. Nejat Aydin
M. Nejat Aydin

Reputation: 10133

Simply use the -o and -u options of sort:

sort -o file -u file

You don't need even to use a pipe for another command, such as uniq.

Upvotes: 7

Ed Morton
Ed Morton

Reputation: 204628

With GNU awk for "inplace" editing:

awk -i inplace '!seen[$0]++' file1.txt

As with all tools (except ed which requires the whole file to be read into memory first) that support "inplace" editing (sed -i, perl -i, ruby -i, etc.) this uses a temp file behind the scenes.

With any awk you can do the following with no temp files used but about twice the memory used instead:

awk '!seen[$0]++{a[++n]=$0} END{for (i=1;i<=n;i++) print a[i] > FILENAME}' file

Upvotes: 3

choroba
choroba

Reputation: 242363

With Perl's -i:

perl -i -lne 'print unless $seen{$_}++' original.file
  • -i changes the file "in place";
  • -n reads the input line by line, running the code for each line;
  • -l removes newlines from input and adds them to print;
  • The %seen hash idiom is described in perlfaq4.

Upvotes: 2

glenn jackman
glenn jackman

Reputation: 247210

A common idiom is:

temp=$(mktemp)
some_pipeline < original.file > "$temp" && mv "$temp" original.file

The && is important: if the pipeline fails, then the original file won't be overwritten with (perhaps) garbage.

The Linux moreutils package contains a program that encapsulates this away:

some_pipeline < original.file | sponge original.file

Upvotes: 1

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