Reputation: 45
const ob = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7
}
}
}
}
}
};
Any methods to solve this code?
I have no idea how to solve this code.
For abovementioned input I would expect a result of 1 + 3 + 6 + 3 + 5 + 7 = 25. So what I want to return from a function sumObject(ob) is: 25
Upvotes: 3
Views: 336
Reputation: 2372
const ob = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7
}
}
}
}
}
};
const sum = data =>
Object
.keys(data)
.reduce((a,b) => a + (typeof(s = data[b]) == "number" ? s : sum(s)), 0);
console.log(sum(ob))
Upvotes: 0
Reputation: 386578
You could get the value of the objects and check if the value is an object, then take the result of the nested objects or call the handed over sum function for accumulator and actual value.
This approach works with a function which takes
This function works as well for getting all values with different accumulator function and an array as startValue
.
const
reduce = (object, fn, startValue) => Object
.values(object)
.reduce(
(r, v) => v && typeof v === 'object' ? reduce(v, fn, r) : fn(r, v),
startValue
),
data = { a: 1, b: { c: 3, d: 6, e: { f: { g: 3, h: { i: 5, j: { k: 7 } } } } } },
total = reduce(data, (a, b) => a + b, 0);
console.log(total);
Upvotes: 0
Reputation: 1926
Try recursion. This will support any amount of nested object at any level of nesting.
const sumAllNumbers = (object, total = 0) => {
const nextValues = [];
for (const value of Object.values(object)) {
if (typeof value === 'number') total += value;
if (typeof value === 'object') nextValues.push(Object.values(value));
}
if (!nextValues.length) return total;
return sumAllNumbers(nextValues.flat(), total);
};
// adds up to 25
const testCase1 = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7,
},
},
},
},
},
};
// adds up to 30
const testCase2 = {
a: 1,
b: 2,
c: {
a: 1,
b: 2,
c: 3,
d: {
a: 5,
b: {
c: {
d: {
e: 1,
},
},
},
},
},
d: {
g: {
f: {
c: 10,
},
},
},
e: {
f: {
a: 1,
g: {
a: 4,
},
},
},
};
// Your original test case
console.log(sumAllNumbers(testCase1));
// My much more demanding test case
console.log(sumAllNumbers(testCase2));
Upvotes: 0
Reputation: 380
If you don't understand some of the other answers, this is an easier solution to understand:
function sumObject(obj){
let result = 0;
for(let i of Object.values(obj)){ //we iterate through all values in obj
if(typeof i == "number"){ //if the current value of i is a number
result+=i; //then add that to the result
} else { //otherwise, it will be an object
result+=sumObject(i); //so we call the function on itself to iterate over this new object
}
}
return result; //finally, we return the total
}
console.log(sumObject(ob));
Upvotes: 1
Reputation: 22534
You can recursively sum the value of each object using array#reduce
and Object.values()
const ob = { a: 1, b: { c: 3, d: 6, e: { f: { g: 3, h: { i: 5, j: { k: 7 } } } } } },
getSum = o =>
Object.values(o).reduce((s, v) => {
s += typeof v === 'object' ? getSum(v): v;
return s;
}, 0);
console.log(getSum(ob));
Upvotes: 0
Reputation: 15520
You can try reduce
with recursion
The condition for the sum is
result
sumObject
recursively with current result
const ob = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7
}
}
}
}
}
};
function sumObject(data, result = 0) {
return Object.values(data).reduce((sum, value) => typeof value === 'number' ? sum + value : sumObject(value, sum), result)
}
console.log(sumObject(ob))
Upvotes: 5
Reputation: 4023
You can do this to extract all values into an array of numbers and then sum that array:
const getObjectValues = (obj) => (obj && typeof obj === 'object')
? Object.values(obj).map(getObjectValues).flat()
: [obj]
let nums = getObjectValues(ob)
let sum = nums.reduce((a, b) => a + b, 0)
Upvotes: 0