Reputation: 90
I am building a react app.
I want to show a popup window in the center of screen in which user can give review to the product.
While showing that window how to prevent scrolling of background and disable all background such that if user clicks outside of that window(even on a button) only that window should disappear?
I want to do something like this:
I have not idea about how it is done.
Please suggest just some way of doing that or suggest some topics which can be used here.
Upvotes: 0
Views: 1580
Reputation: 450
width: 100vw;
height: 100vh;
position: fixed;
z-index: 99;
let myEl = document.getElementById("hideScreen")
//myEl.style.display = "block";
addEventListener("click", () => {
myEl.style.display = "block";
})
#hideScreen {
top:0; left: 0;
width: 100%;
height: 100%;
position: fixed;
background: rgba(50,50,50,0.9);
display: none;
}
input {
margin: 50vmin;
}
<body>
Some text to be vanished.
Click to activate.
<div id="hideScreen">
<input type="text" id="userReview" placeHolder="your review"></input>
</div>
</body>
Upvotes: 1