CODEWITHSUNDEEP
java
matt
matt

Reputation: 25

Is there a better way to verify that one looped list is contained in another in Java?

I am struggling to get the desired result when verifying to see if one list is contained in the other. I am not too sure how to handle it.

List 1:

 List<WebElement> allValues = driver.findElement(By.xpath("//*[@id='allvalues']"));
    
        List<String> list1 = new ArrayList<>();
        for (WebElement all:allValues) {
          String s = all.getText().trim();
          list1.add(s);
        }
System.out.println(list1)

output:

"demo1", "demo2", "demo3", "demo4", "demo5"

List 2:

 List<WebElement> partValues= driver.findElement(By.xpath("//*[@id='partvalues']"));
    List<String> list2= new ArrayList<>();
    
        for (WebElement part: partValues) {
          String t = part.getText().trim();
          list2.add(t);
        }
System.out.println(list2)

output:

"demo2", "demo3", "demo4"

I want to verify that list1 contains all of list 2. I tried a simple boolean verification method like:

System.out.println(list1.containsAll(list2)); and System.out.println(list2.containsAll(list1)). Both returned false and that should not be te case.

What's the most reliable way to verify that list1 contains list2?

Upvotes: 0

Views: 33

Answers (1)

Basil Bourque
Basil Bourque

Reputation: 338795

List#containsAll works as documented, and does what you want.

I copy-pasted your example data.

List< String > list1 = List.of( "demo1", "demo2", "demo3", "demo4", "demo5" ) ;
List< String > list2 = List.of( "demo2", "demo3", "demo4" ) ;
boolean contained = list1.containsAll( list2 ) ;

See code run live at Ideone.com.

contained = true

Upvotes: 1

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