Reputation: 19
I have written the following code
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial- scale=1.0">
<title>contact.dat</title>
<body>
<div id="demo">
<h2>Retrive data by ajax</h2>
<button type="button" onclick="printdata()">Retrive data</button>
</div>
<script>
function printdata() {
const xhttp = new XMLHttpRequest();
xhttp.onload = function() {
document.getElementById("demo").innerHTML +=this.responseText;
}
xhttp.open("GET", "contact.dat");
xhttp.send();
}
</script>
</body>
<?php
$fp = fopen('contact.dat', 'r');
echo "<table border=1>";
echo "<tr><th>Sr. No.</th><th>Name</th><th>Residence No.</th><th>Mob.
no.</th><th>Address</th></tr>";
while ($row = fscanf($fp, "%s %s %s %s %s")) {
echo "<tr>";
foreach ($row as $r) {
echo "<td>$r</td>";
}
echo "</tr>";
}
echo "</table>";
fclose($fp);
?>
</html>
its showing me
I want to show data when I click on the button.
I'm new in both JavaScript as well as PHP.
is there any way to perform something like
if(isset(printdata();))
then run php code block???
Upvotes: 1
Views: 56
Reputation: 19033
Here lies the wrong
/usr/bin/env /opt/jdk17/bin/java .... java.ASG6Ba
Probably the file that you try to execute is ASG6Ba.java
.
The provided file java.ASG6Ba
with the ending ASG6Ba
makes no sense for java to be executed.
Also java
is a prohibited name for packages in java and since the file provided is java.ASG6Ba
, java thinks that java
is a package name and then follows the class name ASG6Ba
. This is the specific reason the error is thrown.
Prohibited package name: java
This is also described in java documentation in chapter 6.1
The first component of a package or module name must not be the identifier java. Package and module names that start with the identifier java are reserved for packages and modules of the Java SE Platform
Upvotes: 1