Reputation: 27
I'm trying to print a large list of phone numbers. In this context, phone numbers have a format (24)999999999
. (Parenthesis for clarity, they are incidental.) I need this list to be randomized, with certain constraints.
The first two digits must be between 11
and 24
,
the following two, which will be the the third and the fourth digits, must be between 67
and 99
.
This is what I've done so far:
ddd = list(range(11, 24))
op = list(range(67, 99))
list1 = list(range(100, 999))
list2 = list(range(1234, 9999))
for d in ddd:
ddd = d
#print(ddd)
for fixos in op:
pre = fixos
#print(pre)
for l in list1:
part1 = l
#print(part1)
for x in list2:
part2 = x
#print(part2)
#print(f"({ddd}) {pre}{l}-{l2}")
numbers = str(ddd) + str(pre) + str(l) + str(x)
#print(numbers)
requests.urllib3.disable_warnings()
The list1
and list2
compose the rest of the number, which should be as random as possible.
However when I run the script it prints like this
numbers : 11671001000
numbers : 11671001001
It goes one by one. Sadly, that's not what I intended to do. How do I get it randomized?
Upvotes: 1
Views: 163
Reputation: 21239
I'd like to propose a different solution:
from random import shuffle
from itertools import cycle
from pprint import pprint
country_code = list(range(11, 24))
operator_code = list(range(67, 99))
exchange_code = list(range(100, 999))
terminal_code = list(range(1234, 9999))
target_len = 100000
ls = set()
while len(ls) < target_len:
shuffle(country_code)
shuffle(operator_code)
shuffle(exchange_code)
shuffle(terminal_code)
numbers = zip(cycle(country_code), cycle(operator_code), cycle(exchange_code), terminal_code)
for c, o, e, t in numbers:
ls.add(f"{c} {o}{e}-{t}")
pprint(ls)
print(len(ls))
# To randomize final output
ls = [i for i in ls]
shuffle(ls)
The output here is ordered because sets are ordered, but it makes some improvements on randomization using shuffle and cycle, and ensures you aren't repeating a number using the constraints of a set
. Mostly I offer it as a way to think about the randomization differently - while selecting a random number with replacement (randint
) is a route, shuffle()
and choice()
are both good ways to ensure randomness, and you can do things with zip()
and cycle()
to essentially create randomized streams that you're choosing from.
The real way to go about this would be to create a generator function - I'd have to think a little harder how to go about that, but it's also a possible solution here.
Upvotes: 1
Reputation: 26
you can try this code it make 100,000 number also you can edit range 100,000 to your goal number
import random
ddd = list(range(11, 25))
op = list(range(67, 100))
for i in ddd:
for j in op:
beg=(str(i)+str(j))
for p in range(100000):
random_number=random.randint(1000000, 10000000)
print(beg+str(random_number))
Upvotes: 1