Reputation: 73
`select
order_price,
To_char(to_date(order_date,'YYYY-MM-DD HH24:MI:SS'),'yyyymmdd hh24') as order_date,
SUM(order_price) OVER(ORDER BY To_char(to_date(order_date,'YYYY-MM-DD HH24:MI:SS'),'yyyymmdd
hh24')) as "bth"
from order_tbl
where seller_no=100
order by order_date;`
I got this result.
But the data I want to get is as follows.
20000 / 20220524 15 / 52500
13000 / 20220524 15 / 52500
19500 / 20220524 15 / 52500
19600 / 20220524 16 / 72100
222000 / 20220524 17 / 738700
and even if there is no data...
0 / 20220524 18 / 738700
0 / 20220524 19 / 738700
0 / 20220524 20 / 738700 .
.
.
.
0 / 20220525 10 / 738700
13600 / 20220525 11 / 787300
like this.
I want to get the order_date and bth for every hour even if there is no data.
It's too difficult for me, but how can I do?
i will remove order_price and add distinct later.
Upvotes: 0
Views: 66
Reputation: 615
You can try this: (read the guide below)
WITH all_hour AS (
SELECT LEVEL AS hour
FROM dual
CONNECT BY LEVEL <= 24
),
all_date AS (
SELECT TO_CHAR(DATE'2022-05-24' + LEVEL - 1, 'YYYYMMDD') AS dt
FROM dual
CONNECT BY LEVEL <= (DATE'2022-05-27' - DATE'2022-05-24' + 1)
),
all_date_hour AS (
SELECT dt || ' ' || (CASE WHEN hour < 10 THEN '0' || TO_CHAR(hour) ELSE TO_CHAR(hour) END) AS order_date
FROM all_date
CROSS JOIN all_hour
),
your_order AS (
SELECT
order_price,
TO_CHAR(TO_DATE(order_date,'YYYY-MM-DD HH24:MI:SS'),'YYYYMMDD HH24') AS order_date,
seller_no
FROM order_tbl
),
your_sum AS (
SELECT adh.order_date, SUM(CASE WHEN yo.seller_no = 100 THEN yo.order_price ELSE 0 END) AS bth
FROM all_date_hour adh
LEFT JOIN your_order yo ON adh.order_date = yo.order_date
GROUP BY adh.order_date
)
SELECT order_date, SUM(bth) OVER(ORDER BY order_date) AS bth
FROM your_sum
ORDER BY order_date;
Summary:
(1) Table 1 : all_hour
(2) Table 2 : all_date
(3) Table 3 : all_date_hour
(4) Table 4: your_order
(5) Table 5: your_sum (NOT ACCUMULATED YET)
case
statement (Line 24)SUM(CASE WHEN yo.seller_no = 100 AND youradditionalcondition = somecondition THEN yo.order_price ELSE 0 END)
(6) Final Select Query:
SUM() OVER(ORDER BY *yourexpr*)
Upvotes: 1
Reputation: 3256
You can use this query - explained later:
select
to_date('01/01/2022 00:00:00','dd/mm/yyyy hh24:mi:ss') + all_hours.sequence_hour/24 order_date_all,
order_price,
To_char(order_date, 'yyyymmdd hh24') as order_date_real,
SUM(order_price) OVER(ORDER BY To_char(order_date, 'yyyymmdd hh24')) as "bth"
from order_tbl ,
(SELECT LEVEL sequence_hour
FROM dual
CONNECT BY LEVEL <= 10) all_hours
where trunc((order_date(+)-to_date('01/01/2022 00:00:00','dd/mm/yyyy hh24:mi:ss'))*24) = all_hours.sequence_hour
and seller_no(+)=100
order by 1;
Explanation:
Upvotes: 1