CODEWITHSUNDEEP
pythonedx
majk
majk

Reputation: 1

How do i turn split input into int?

Here's what I have so far. What I'm trying to do is ask the user for an expression, they input something like 1 + 1 and it's split into x, y, and z. Such that x would be 1, y would be + and z would be the second 1. I'm sure there may be several issues but the main one I'm having right now is converting their input into an int.

x, y, z = input("Expression: ").split()

if y == "+":
    output = x + z
    print(output)

elif y == "-":
    output = x - z
    print(output)

elif y == "*":
    output = x * z
    print(output)

elif y == "/":
    output = x / z
    print(output)

Upvotes: -3

Views: 338

Answers (2)

Nipuna Upeksha
Nipuna Upeksha

Reputation: 428

The simplest way to do this would be the way that you were doing. But the catch is you have to have spaces between the numbers and the operators like this. 1 + 1

x, y, z = input("Expression: ").split()

output = 0
x = int(x)
z = int(z)
if y == "+":
    output = x + z
elif y == "-":
    output = x - z
elif y == "*":
    output = x * z
elif y == "/":
    output = x / z
print(output)

But if the input is like the following 1+1 where it contains no spaces, then you might get errors. In order to fix that issue the following simple approach can be taken.

import operator
value = input("Expression: ")
ops = {'+':operator.add, '-':operator.sub, '*':operator.mul , '/':operator.truediv}
for i in ops:
    if i in value:
        x,y = value.split(i)
        x = int(x)
        y = int(y)
        print(ops[i](x,y))

If your python version is 2, you might want to use operators.div instead of operators.truediv.

Upvotes: -1

Tanish Gupta
Tanish Gupta

Reputation: 492

You can try for this:

x, y, z = input("Expression: ").split()

x = int(x)
z = int(z)

if y == "+":
    output = x + z
    print (output)

elif y == "-":
    output = x - z
    print(output)

elif y == "*":
    output = x * z
    print(output)

elif y == "/":
    output = x / z
    print(output)

Upvotes: -1

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