CODEWITHSUNDEEP
pythonpython-3.x
tckraomuqnt
tckraomuqnt

Reputation: 492

How to Compare nested Dictionaries and update missing items in python?

Hai needs to compare two dictionaries. How to Find and update the missing items to the base dictionary.

language_1 = {"kannada" : {"lbl01":"kannada_File","lbl02":"kannada_accounts","lbl03":"kannada_Inventory","lbl04":"kannada_manufacture"},
          "english": {"lbl01": "File", "lbl02": "Accounts", "lbl03": "Inventory", "lbl04": "manufacture"}}
          

language = {"id"      : {"lbl01":"file"      ,"lbl02":"accounts"     ,"lbl03":"inventory"       ,"lbl04":"manufacture"},
            "english" : {"lbl01":"File"      ,"lbl02":"Accounts"     ,"lbl03":"Inventory"       ,"lbl04":"manufacture"},
            "tamil"   : {"lbl01":"கோப்பு"    ,"lbl02":"கணக்கியல்"   ,"lbl03":"சரக்கியல்"       ,"lbl04":"உற்ப்பத்தி"},
            "hindi"   : {"lbl01":"Hindi_File","lbl02":"Hindi_accounts","lbl03":"Hindi_Inventory","lbl04":"Hindi_manufacture"}}

For example "language" is my base dictionary. I want to check, whether the items in "langugae_1" is found in a base dictionary or not. If Not found, then add it into the base dictionary. In my case "kannada" is not found in my base dictionary, so add it into the base dictionary. How to resolve it?

Upvotes: 1

Views: 222

Answers (5)

Sharim09
Sharim09

Reputation: 6224

Simple and understandable way.


language_1 = {"kannada" : {"lbl01":"kannada_File","lbl02":"kannada_accounts","lbl03":"kannada_Inventory","lbl04":"kannada_manufacture"},
          "english": {"lbl01": "File", "lbl02": "Accounts", "lbl03": "Inventory", "lbl04": "manufacture"}}


language = {"id"      : {"lbl01":"file"      ,"lbl02":"accounts"     ,"lbl03":"inventory"       ,"lbl04":"manufacture"},
            "english" : {"lbl01":"File"      ,"lbl02":"Accounts"     ,"lbl03":"Inventory"       ,"lbl04":"manufacture"},
            "tamil"   : {"lbl01":"கோப்பு"    ,"lbl02":"கணக்கியல்"   ,"lbl03":"சரக்கியல்"       ,"lbl04":"உற்ப்பத்தி"},
            "hindi"   : {"lbl01":"Hindi_File","lbl02":"Hindi_accounts","lbl03":"Hindi_Inventory","lbl04":"Hindi_manufacture"}}

for a in language_1:
    if not any(language[b] == language_1[a] for b in language):
        count = list(language).count(a)
        if count:
            language[a+str(count)] = language_1[a]
        else:
            language[a] = language_1[a]

print(language)

I know a simple way is language.update(language_1) but If you want to check Every nested dictionary then use this.

Means

d = {'a':[1,2,3]}

full_d = {'a':[1,2]}

# Here full_d['a'] != d['a'], THen this make another key but with the serial number.

# OUTPUT

{'a':[1,2],'a1':[1,2,3]}

OR Try this (Suggested First One)

for a in language_1:
    if not any(language[b] == language_1[a] for b in language):
        count = list(language).count(a)
        if count == 1:
            language[a+str(count)] = language[a]
            del language[a]
        if count:
            language[a+str(count+1)] = language_1[a]
        else:
            language[a] = language_1[a]

print(language)

d = {'a':[1,2,3]}

full_d = {'a':[1,2]}

# Here full_d['a'] != d['a'], THen this make another key but with the serial number.

# OUTPUT

{'a1':[1,2],'a2':[1,2,3]}

Upvotes: 2

Akshay Kumar
Akshay Kumar

Reputation: 467

You can just simply assign it like this

for key in language_1.keys():
if key not in language.keys():
    language[key]=language_1[key]

Upvotes: 1

tushar_ecmc
tushar_ecmc

Reputation: 188

There is an inbuilt python dictionary method to do exactly the same You can use dict.update() method to achieve this.

In your case. First you need to copy your data from language_1 to some variable(If you want to keep language_1 intact)

temp = language_1.copy()

Then you can perform update

temp.update(language)

Copy the data to language variable

language = temp.copy()

Upvotes: 1

SCcagg5
SCcagg5

Reputation: 648

Quite a simple answer:

language.update(language_1)

Upvotes: 1

Glauco
Glauco

Reputation: 1463

It seems a simple question. the dictionary has the .update() function.

language.update(language_1)

or if you need to apply some filter-logic

language.update({k:v for k,v in language_1.items() if <some logic>})

here some example and here

If you need some sophisticated logic, dictdiffer can be a very useful pakcage

Upvotes: 2

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