CODEWITHSUNDEEP
pythonregex
Mond Wan
Mond Wan

Reputation: 1912

Unable to use conditional regex to test my string in python

I would like to write a regex to fulfil following requirements:

Test case Test string Is Valid
1 board add 0/1 aaa True
2 board add 0/1 xxx False
3 EMPTY_STRING True
4 True
5 board add 0/2 aaa True

Then, I decided to build the regex with python by make use of

(?(xxx)YES-PATTERN|NO-PATTERN)

I come up with following

But, the regex above just does not work as expected. It failed on test case 2. Anyone know how to fix it?

You can check my regex by following url

https://regex101.com/r/M8UEsb/1

Upvotes: 0

Views: 64

Answers (2)

The fourth bird
The fourth bird

Reputation: 163467

You are not matching the 2 in example nr. 5, only the 1.

But as the group 1 value is optional, and you only test for group 1 in the if/else clause, it can match at any position and the pattern is also unanchored.

You could also write an alternation that allows all the patterns instead of using if/else:

^[^\S\n]*(?:board add 0/[12] (?:aaa|bbb))?$

Explanation

  • ^ Start of string
  • [^\S\n]* Mach optional spaces without newlines
  • (?: Non capture group
    • board add 0/[12] Match the string ending on either 1 or 2
    • (?:aaa|bbb) Match one of the alternatives
  • )? Close the group
  • $ End of string

Regex demo

Example

import re

strings = ["board add 0/1 aaa", "board add 0/1 xxx", "", "    ", "board add 0/2 aaa"]

for s in strings:
    m = re.match(r"^[^\S\n]*(?:board add 0/[12] (?:aaa|bbb))?$", s)
    print(f"'{s}' ==> {bool(m)}")

Output

'board add 0/1 aaa' ==> True
'board add 0/1 xxx' ==> False
'' ==> True
'    ' ==> True
'board add 0/2 aaa' ==> True

Upvotes: 2

Artyom Vancyan
Artyom Vancyan

Reputation: 5390

This pattern checks the existence of aaa or bbb if the string starts with board add 0/1 or board add 0/2. And if any of board add 0/1 and board add 0/2 does not exist, it passes.

^(?:(?!board add 0/[12]).)*$|board add 0/[12] (?:aaa|bbb)

Regex Explanation

  • ^ Start of a string
  • (?: Non-capturing group
    • (?! Negative lookahead assertion - assert that the following regex does not match
      • board add 0/[12] Match board add 0/1 or board add 0/2
    • ) Close lookahead
    • . Any character except newline
  • ) Close non-capturing group
  • * The previous match can be matched zero or more times
  • $ End of a string
  • | OR. If the whole previous pattern did not match then check the next
  • board add 0/[12] Match board add 0/1 or board add 0/2
  • (?: Non-capturing group
    • aaa|bbb Match aaa or bbb
  • ) Close non-capturing group

See the demo

Python Example

import re

strings = [
    'board add 0/1 aaa',
    'board add 0/1 xxx',
    '',
    '                 ',
    'board add 0/2 aaa'
]

for string in strings:
    print(bool(re.match(r'^(?:(?!board add 0/[12]).)*$|board add 0/[12] (?:aaa|bbb)', string)))

Output

True
False
True
True
True

Upvotes: 1

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