CODEWITHSUNDEEP
groovyxml-parsing
Colselaw
Colselaw

Reputation: 1079

Groovy: Node.replaceNode with Node?

Suppose I have a node I'd like to replace with replaceNode, however, I don't want to use a Builder to do it - or rather, I already have the node with which to replace it:

replacement = new XmlParser.parse('input.xml')
root.depthFirst().replaceme.each { it ->
  it.replaceNode { node ->
    // This is what I can't figure out
  }
}

I've tried lots of different iterations, but can't seem to work it out. If I just return text in that segment, it replaces the node with an empty node.

For example, if my input file is this: This should get replaced

And I have a replacement like this: This will replace the Original

I'd like to do something like:

top = new XmlParser().parseFile('input.xml')
top.middle.each { it ->
  it.replaceNode { node ->
    new XmlParser().parseFile('replacement.xml')
  }
}

Upvotes: 1

Views: 4601

Answers (1)

schmolly159
schmolly159

Reputation: 3881

If you don't mind switching to XmlSlurper() the following should work:

def top = new XmlSlurper().parse('input.xml')
top.middle.each { node ->
    node.replaceNode {
        mkp.yield(new XmlSlurper().parse('replacement.xml')) 
    }   
}

Which will replace all middle nodes with the contents of replacement.xml

Upvotes: 2

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