CODEWITHSUNDEEP
c++iostreamcoutiomanip
Givikap120
Givikap120

Reputation: 71

How to get non scientific output while still not outputing zeros in std::cout?

Here's is an example:

std::cout << 1000000.0 << "\n";
std::cout << std::fixed << 1000000.0 << "\n";
std::cout << std::fixed << std::noshowpoint << 1000000.0 << "\n";

It will print me this:

1e+06
1000000.000000
1000000.000000

But I want this:

1000000

How I can do it with IO manipulators without setprecision()? Why without? Because I want to print:

std::cout << 1000000.0 << " " << 1111111.1 << " " << 1234567.89;

and get:

1000000 1111111.1 1234567.89

without calculating precision for every number

Upvotes: 2

Views: 80

Answers (1)

Givikap120
Givikap120

Reputation: 71

The scientific output is used when the digits count of the number is higher than precision. For example, the default precision is equal to 6, but the number 1234567 has 7 digits, so it will be printed as 1.23457+e06, cutting off the last digit. So to get 1234567 printed normally we need at least precision = 7. The highest precision that is not adding the "wrong" numbers is 15, so you need to use std::setprecision(15).

code: std::cout << std::setprecision(15) << 1000000.0 << " " << 1111111.1 << " " << 1234567.89;

out: 1000000 1111111.1 1234567.89

Upvotes: 1

Related Questions