CODEWITHSUNDEEP
assemblyarmarm64neon
ALPHA
ALPHA

Reputation: 79

What kind of assembly instruction is this ld1 {v4.16b - v7.16b}, [x10]?

The below assembly instruction is AArch64 NEON / ASIMD assembly code.

ld1 {v4.16b - v7.16b}, [x10]

and found some related page about ld1 instruction. but there are no reference about minus(-) symbol using in ld1 assembly instruction. What does it mean?

I guess... it means to put continuous data from the address x10 to the 3rd to 7th vector, is that correct?

Upvotes: 1

Views: 215

Answers (1)

fuz
fuz

Reputation: 92966

Yes, your understanding is correct. {v4.16b-v7.16b} is just shorthand for {v4.16b, v5.16b, v6.16b, v7.16b}.

So this instruction loads 64 bytes from [x10] and stores them into v4, v5, v6, and v7 without any deinterleaving.

Upvotes: 2

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