CODEWITHSUNDEEP
pythonlogictruthiness
Caleb
Caleb

Reputation: 11

CodeBat Python - Logic 1 - where is the error in my logic?

The question, my answer, and the output is screenshotted here

Constraints:

0=no ticket
1=small ticket
2=big ticket.

If speed is 60 or less, the result is 0. If speed is between 61 and 80 inclusive, the result is 1. If speed is 81 or more, the result is 2. Unless it is your birthday -- on that day, your speed can be 5 higher in all cases.

My Code:

def caught_speeding(speed, is_birthday):
  
  if speed > 80 or (speed > 85 and is_birthday):
    return 2
  return int((60 < speed <= 80) or (65 < speed <= 85 and is_birthday))

caught_speeding(65, True) gives 1 but should be 0

caught_speeding(85, True) gives 2 but should be 1

the other tests are ok. When I trace the code I cant seem to find the error

Upvotes: 1

Views: 55

Answers (2)

Cardstdani
Cardstdani

Reputation: 5223

You can come up with a one-liner solution using the following logic, subtracting 5 from speed when is_birthday parameter gets a True value:

def caught_speeding(speed, is_birthday):
  if is_birthday:
      speed -= 5
  return 0 if speed < 60 else 1 if speed <= 80 and speed >= 61 else 2 if speed >= 81 else 0

print(caught_speeding(81, 0))
print(caught_speeding(65, True))
print(caught_speeding(85, True))

Output:

2
0
1

Upvotes: 0

Tom Karzes
Tom Karzes

Reputation: 24052

For caught_speeding(65, True), the first condition is false so it falls through to the return statement. In that case, (60 < speed <= 80) is true, since 65 falls within that range. The other condition doesn't matter since it's joined with an or, so it's effectively doing return int(True) which is 1.

For caught_speeding(85, True), the speed > 80 condition is true, since 85 is greater than 80. Again, the other condition doesn't matter since it's joined with an or, so it executes the return 2 statement.

Upvotes: 1

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