CODEWITHSUNDEEP
regexpcre2
Chebz
Chebz

Reputation: 1395

Regex using recursion with groups

I am not certain if there's any regex magic that can do this:

foo(f1, f2()) = bar { b1, b2 {}} //match all of this
foo(f3) // dont match this
bar{b3} // dont match this

what I am trying to do is capture an entire line if it contains this pattern:

\w+\((?:[^()]|(?RECURSION ON PARENTHESES))*\)\s*=\s*\w+{(?:[^{}]|(?RECURSION ON CURLY BRACKETS))*}

Upvotes: 0

Views: 244

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626870

You can use regex subroutines:

\w+\s*(\((?:[^()]++|(?-1))*\))\s*=\s*\w+\s*({(?:[^{}]++|(?-1))*})

See the regex demo.

Details:

  • \w+ - one or more word chars
  • \s* - zero or more whitespaces
  • (\((?:[^()]++|(?-1))*\)) - a substring between paired nested parentheses
  • \s*=\s* - a = char enclosed with zero or more whitespaces
  • \w+\s* - one or more word chars, zero or more whitespaces
  • ({(?:[^{}]++|(?-1))*}) - a substring between paired nested curly braces.

Note the (?-1) recurses the latest capturing group pattern.

Upvotes: 1

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