Reputation: 4468
I'm trying to learn Rust after many years of C++. I have a situation where the compiler is complaining about a borrow, and it doesn't seem to matter whether it is mutable or immutable. I don't seem to be able to use self
as a parameter inside a loop that start with: for item in self.func.drain(..)
.
I've tried calling appropriate()
as a function:
Self::appropriate(&self,&item,index)
and I have tried it as a method:
self.appropriate(&item,index)
but I get the same message in either case:
The function or method appropriate()
is intended imply examine the relationship among its parameters and return a bool
without modifying anything. How can I call either a function or method on self
without violating borrowing rules?
This program is a learning exercise from exercism.org
and doesn't include a main()
so it won't run but should almost compile except for the error in question. Here's the code I have:
use std::collections::HashMap;
pub type Value = i32;
pub type Result = std::result::Result<(), Error>;
pub struct Forth {
v: Vec<Value>,
f: HashMap<String,usize>,
s: Vec<Vec<String>>,
func: Vec<String>
}
#[derive(Debug, PartialEq)]
pub enum Error {
DivisionByZero,
StackUnderflow,
UnknownWord,
InvalidWord,
}
impl Forth {
pub fn new() -> Forth {
let mut temp: Vec<Vec<String>> = Vec::new();
temp.push(Vec::new());
Forth{v: Vec::<Value>::new(), f: HashMap::new(), s: temp, func: Vec::new()}
}
pub fn stack(&self) -> &[Value] {
&self.v
}
pub fn eval(&mut self, input: &str) -> Result {
self.v.clear();
self.s[0].clear();
let mut count = 0;
{
let temp: Vec<&str> = input.split(' ').collect();
let n = temp.len() as i32;
for x in 0..n as usize {
self.s[0].push(String::from(temp[x]));
}
}
let mut collecting = false;
let mut xlist: Vec<(usize,usize)> = Vec::new();
let mut sx: usize = 0;
let mut z: i32 = -1;
let mut x: usize;
let mut n: usize = self.s[0].len();
loop {
count += 1;
if count > 20 {break;}
z += 1;
x = z as usize;
if x >= n {break;}
z = x as i32;
let word = &self.s[sx][x];
if word == ";" {
if collecting {
collecting = false;
let index: usize = self.s.len();
self.s.push(Vec::<String>::new());
for item in self.func.drain(..) {
if self.s[index].len() > 0 &&
Self::appropriate(&self,&item,index)
{
let sx = *self.f.get(&self.s[index][0]).unwrap();
let n = self.s[sx].len();
for x in 1..n as usize {
let symbol = self.s[sx][x].clone();
self.s[index].push(symbol);
}
}
else {
self.s[index].push(item);
}
}
self.f.insert(self.s[index][0].clone(), index);
self.func.clear();
continue;
}
if 0 < xlist.len() {
(x, n) = xlist.pop().unwrap();
continue;
}
return Err(Error::InvalidWord);
}
if collecting {
self.func.push(String::from(word));
continue;
}
if Self::is_op(word) {
if self.v.len() < 2 {
return Err(Error::StackUnderflow);
}
let b = self.v.pop().unwrap();
let a = self.v.pop().unwrap();
let c = match word.as_str() {
"+" => a + b,
"-" => a - b,
"*" => a * b,
"/" => {if b == 0 {return Err(Error::DivisionByZero);} a / b},
_ => 0
};
self.v.push(c);
continue;
}
match word.parse::<Value>() {
Ok(value) => { self.v.push(value); continue;},
_ => {}
}
if word == ":" {
collecting = true;
self.func.clear();
continue;
}
if word == "drop" {
if self.v.len() < 1 {
return Err(Error::StackUnderflow);
}
self.v.pop();
continue;
}
if word == "dup" {
if self.v.len() < 1 {
return Err(Error::StackUnderflow);
}
let temp = self.v[self.v.len() - 1];
self.v.push(temp);
continue;
}
if !self.f.contains_key(word) {
return Err(Error::UnknownWord);
}
xlist.push((sx,n));
sx = *self.f.get(word).unwrap();
n = self.s[sx].len();
z = 0;
}
Ok(())
}
fn is_op(input: &str) -> bool {
match input {"+"|"-"|"*"|"/" => true, _ => false}
}
fn appropriate(&self, item:&str, index:usize) -> bool
{
false
}
fn prev_def_is_short(&self, index: usize) -> bool {
if index >= self.s.len() {
false
}
else {
if let Some(&sx) = self.f.get(&self.func[0]) {
self.s[sx].len() == 2
}
else {
false
}
}
}
}
The error message relates to the call to appropriate()
. I haven't even written the body of that function yet; I'd like to get the parameters right first. The compiler's complaint is:
As a subroutine call
error[E0502]: cannot borrow `self` as immutable because it is also borrowed as mutable
--> src/lib.rs:85:47
|
81 | for item in self.func.drain(..) {
| -------------------
| |
| mutable borrow occurs here
| mutable borrow later used here
...
85 | Self::appropriate(&self,&item,index)
| ^^^^^ immutable borrow occurs here
For more information about this error, try `rustc --explain E0502`.
as a method call
error[E0502]: cannot borrow `*self` as immutable because it is also borrowed as mutable
--> src/lib.rs:85:29
|
81 | for item in self.func.drain(..) {
| -------------------
| |
| mutable borrow occurs here
| mutable borrow later used here
...
85 | self.appropriate(&item,index)
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ immutable borrow occurs here
For more information about this error, try `rustc --explain E0502`.
Is there any canonical way to deal with this situation?
Upvotes: 2
Views: 927
Reputation: 16785
The problem is that self.func.drain()
will consume the elements contained in self.func
, thus an exclusive (&mut
) access is needed on self.func
for the entire for
loop.
If during the iteration you need to pass a reference to self
globally, then its func
member is potentially accessible while the loop holds an exclusive access to it: Rust forbids that.
Since you use drain()
in order to consume all the elements inside self.func
, I suggest you swap this vector with an empty one just before the loop, then iterate on this other vector that is not anymore part of self
.
No copy of the content of the vector is involved here; swap()
only deals with pointers.
Here is an over-simplified version of your code, adapted consequently.
struct Forth {
func: Vec<String>,
}
impl Forth {
fn eval(&mut self) {
/*
for item in self.func.drain(..) {
self.appropriate(&self);
}
*/
let mut func = Vec::new();
std::mem::swap(&mut self.func, &mut func);
for item in func.drain(..) {
let b = self.appropriate();
println!("{:?} {:?}", item, b);
}
}
fn appropriate(&self) -> bool {
false
}
}
fn main() {
let mut f = Forth {
func: vec!["aaa".into(), "bbb".into()],
};
f.eval();
}
Upvotes: 3