CODEWITHSUNDEEP
spring-data-jpahibernate-criteria
Prashant kamble
Prashant kamble

Reputation: 329

Parameter value [\] did not match expected type [java.lang.String (n/a)]

Getting below exception for 2nd call onwards.We are using hibernate 5.6.6.Final

"message": "Parameter value [\] did not match expected type [java.lang.String (n/a)]; nested exception is java.lang.IllegalArgumentException: Parameter value [\] did not match expected type [java.lang.String (n/a)]",

Upvotes: 2

Views: 14649

Answers (2)

Arquímedes-X9000
Arquímedes-X9000

Reputation: 11

You must check if that field is an inner join, in that case you must go to the entity that is relating to your current entity.

Example:

  @Table(name = "table_item")
    public class DetalleSolicitudArchivo

You need get detail_id:

@ManyToOne
    @JoinColumn(name = "table_detail_item_id")
    private Carpeta carpeta;


 @Column(name = "detail_item_id")
private Long detailItemId

I hope this you help.

Upvotes: 0

Viktar Patotski
Viktar Patotski

Reputation: 663

You are facing a bug introduced in Hibernate 5.6.6.Final and fixed in 5.6.9.Final: https://hibernate.atlassian.net/browse/HHH-15142

Just upgrade your Hibernate version.

Upvotes: 6

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