Reputation: 4460
Let's say I got this code:
function MinMax(list) {
const min = Math.min(...list);
const max = Math.max(...list);
return {
min,
max,
list,
};
}
const massiveList = [
1,
// supposedly a gazillion
// integer values
10000000,
];
const minMax = MinMax(massiveList);
const minMaxList = minMax.list;
console.log('min ', minMax.min);
console.log('max ', minMax.max);
console.log('minMaxList length', minMaxList.length);
Here's my question: since arguments are passed by value in JavaScript, does that mean, that after that point in code, where minMax.list is assigned to minMaxList, three copies of the original massiveList exist in heap memory?
Upvotes: 0
Views: 91
Reputation: 15540
You can try the below demo with reference value
const massiveList = [
1,
// supposedly a gazillion
// integer values
10000000,
];
const testReference = (list) => {
console.log(list === massiveList) //true
}
testReference(massiveList)
In your case, list
and massiveList
are the same reference which means any modification on list
will be applied on massiveList
as well.
...list
means you've cloned the original list to another list that will be allocated newly in the memory.
The below demo is to show reference values get changed for the new list, so that's why the result is false
const massiveList = [
1,
// supposedly a gazillion
// integer values
10000000,
];
const testReference = (list) => {
const newList = [...list]
console.log(list === newList) //false
}
testReference(massiveList)
Upvotes: 2