Error when parsing string to datetime using datetime.strptime() in ISO 8601 format in Python

Question

I'm trying to parse a string as a datetime, put it as a new timezone (CEST UTC+02) and return it, but I get this error:

> ValueError: time data '2022-07-04T03:15:00Z' does not match format '%Y-%m-%dT%H:%M:%S.%f%z'

Example input:

2022-07-04T03:15:00Z
2022-07-04T12:40:20Z
2022-07-04T11:56:08Z

Example output:

2022-07-04T05:15:00+02:00
2022-07-04T14:40:20+02:00
2022-07-04T13:56:08+02:00

Code:

from datetime import timedelta, datetime

str = "2022-07-04T03:15:00Z"
str = (datetime.strptime(str, '%Y-%m-%dT%H:%M:%S.%f%z') + timedelta(hours=2)).isoformat()
print(str)

I also tried:

str = (datetime.strptime(str, '%Y-%m-%dT%H:%M:%S.000%z') + timedelta(hours=2)).isoformat()

and:

str = (datetime.strptime(str, '%Y-%m-%dT%H:%M:%S.%fz') + timedelta(hours=2)).isoformat()

as suggested by this and by this:

Answer 1

Your format is incorrect, remove the .%f, you have no microseconds:

from datetime import timedelta, datetime

s = "2022-07-04T03:15:00Z"
s = (datetime.strptime(s, '%Y-%m-%dT%H:%M:%S%z') + timedelta(hours=2)).isoformat()
print(s)

Output: 2022-07-04T05:15:00+00:00