CODEWITHSUNDEEP
replaceansibleregexp-replace
Vin
Vin

Reputation: 61

Ansible replace new line with three space followed by newline

I want to replace each “\n” with “ \n” But it shouldn’t replace in places like words having \n “C:\node” how to achieve this.

- set_fact:
    Value: “{{Str.replace(“\n”,”    \n”)}}”

Upvotes: 0

Views: 1618

Answers (2)

Vladimir Botka
Vladimir Botka

Reputation: 68034

Use single-quoted strings and put both regex and replace into variables. Then you have to escape '\' only once. For example,

    - debug:
        var: value
      vars:
        str1: 'C:\node'
        value: "{{ str1|regex_replace(regex, replace) }}"
        regex: '\\n'
        replace: '    \\n'

gives

  value: 'C:    \node'

If you put regex and replace in-line you have to escape twice because of the outside double-quotes. For example, the task below gives the same result

    - debug:
        var: value
      vars:
        str1: 'C:\node'
        value: "{{ str1|regex_replace('\\\\n', '    \\\\n') }}"

You have to escape also twice if you double-quote regex and replace in variables. For example, the task below gives the same result

    - debug:
        var: value
      vars:
        str1: 'C:\node'
        value: "{{ str1|regex_replace(regex, replace) }}"
        regex: "\\\\n"
        replace: "    \\\\n"

Upvotes: 2

OreOP
OreOP

Reputation: 142

The newline character \n is different than the two characters \ and n, so inside your regex if you do not escape the \ of the newline character it should not match the character \ followed by n

For example, the regex \n matches the newline character but nothing in "C:\node" while \\n will match "C:\node"

You can try to experiment with regex yourself in regex101

Upvotes: 0

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