Reputation: 173
I have a collection in mongoDB with documents like:
{
"_id" : ObjectId("some_id"),
"name" : "name",
"field1" : 123,
"field2" : 234,
"arr" : [
{
"a_num" : 3,
"arr" : [
"abc",
"def"
],
},
{
"a_num" : 36,
"arr" : [
"hi"
],
},
{
"a_num" : 34,
"arr" : [
"abc"
],
}
]
}
While I'm using find()
I don't want to get the arr
elements where arr
has only 1 element, that its value is "abc"
.
E.g, for the above document, I'd like to get:
{
"_id" : ObjectId("some_id"),
"name" : "name",
"field1" : 123,
"field2" : 234,
"arr" : [
{
"a_num" : 3,
"arr" : [
"abc",
"def"
],
},
{
"a_num" : 36,
"arr" : [
"hi"
],
},
]
}
Any idea how? Thanks!
Upvotes: 0
Views: 33
Reputation: 22316
You'll need to use the aggregation framework with $filter
, like so:
db.collection.aggregate([
{
$addFields: {
arr: {
$filter: {
input: "$arr",
cond: {
$ne: [
"$$this.arr",
[
"abc"
]
]
}
}
}
}
}
])
Upvotes: 1