CODEWITHSUNDEEP
python
kbb
kbb

Reputation: 3415

Converting a list of integers into a single value

If I had list of integers say, 

x = [1,2,3,4,5]

Is there an in-built function that can convert this into a single number like 12345? If not, what's the easiest way?

Upvotes: 3

Views: 250

Answers (4)

eph
eph

Reputation: 2028

Just for fun :)

int(str(x)[1:-1].replace(', ', ''))

Surprisingly, this is even faster for large list:

$ python -m timeit -s "x=[1,2,3,4,5,6,7,8,9,0]*100" "int(str(x)[1:-1].replace(', ', ''))"
10000 loops, best of 3: 128 usec per loop

$ python -m timeit -s "x=[1,2,3,4,5,6,7,8,9,0]*100" "int(''.join(map(str, x)))"
10000 loops, best of 3: 183 usec per loop

$ python -m timeit -s "x=[1,2,3,4,5,6,7,8,9,0]*100" "reduce(lambda x,y:x*10+y, x, 0)"
1000 loops, best of 3: 649 usec per loop

$ python -m timeit -s "x=[1,2,3,4,5,6,7,8,9,0]*100" "sum(digit * 10 ** place for place, digit in enumerate(reversed(x)))"
100 loops, best of 3: 7.19 msec per loop

But for very small list (maybe more common?) , this one is slowest.

Upvotes: 1

xubuntix
xubuntix

Reputation: 2333

int("".join(str(X) for X in x))

You have not told us what the result for x = [1, 23, 4] should be by the way... My answer gives 1234, others give 334

Upvotes: 2

PaulMcG
PaulMcG

Reputation: 63709

>>> listvar = [1,2,3,4,5]
>>> reduce(lambda x,y:x*10+y, listvar, 0)
12345

Upvotes: 5

Mike Graham
Mike Graham

Reputation: 76683

If they're digits like this, 

sum(digit * 10 ** place for place, digit in enumerate(reversed(x)))

Upvotes: 4

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