Reputation: 23178
I have a bunch of chat logs that look like this:
name: some text
name2: more text
name: text
name3: text
I want to highlight the just the names. I wrote some code that should do it, however, I was wondering if there was a much cleaner way than this:
$line= "name: text";
$newtext = explode(":", $line,1);
$newertext = "<font color=red>".$newtext[0]."</font>:";
$complete = $newertext.$newtext[1];
echo $complete;
Upvotes: 0
Views: 3422
Reputation: 15361
Looks fine, although you can save the temp variables:
$newtext = explode(":", $line,1);
echo "<font color=red>$newtext[0]</font>:$newtext[1]";
This might be faster or might not, you'd have to test:
echo '<font color=red>' . substr_replace($line, '</font>', strpos($line, ':') , 0);
Upvotes: 1
Reputation: 586
also try the RegExp like this:
$line = "name: text";
$complete = preg_replace('/^(name.*?):/', "<font color=red>$1</font>:", $line);
echo $complete ;
EDIT
if their names aren't "name" or "name1", just delete the name in pattern, like this
$complete = preg_replace('/^(.*?):/', "<font color=red>$1</font>:", $line);
Upvotes: 0
Reputation: 3175
The answer posted by gview is the simplest it gets, however and just as a reference you can use a regular expression to find the name tag, and replace it with the new html code using preg_replace() as follows:
// Regular expression pattern
$pattern = '/^[a-z0-9]+:?/';
// Array contaning the lines
$str = array('name: some text : Other text and stuff',
'name2: more text : : TEsting',
'name: text testing',
'name3: text Lorem ipsum');
// Looping through the array
foreach($str as $line)
{
// \\0 references the first pattern match which is "name:"
echo preg_replace($pattern, "<font color=red>\\0</font>:", $line);
}
Upvotes: 1