CODEWITHSUNDEEP
goslice
worrum
worrum

Reputation: 90

How to output iterate over first N elements of slice?

I need to take applicant's first name, second name and GPA, then output only the first N applicants. For example, I have 5 applicants, but only N=3 can pass through. To do this task, I decided to use a slice of struct.

The struct looks like this:

type Applicant struct {
    firstName  string
    secondName string
    GPA        float64
}

I created a slice and initialized it:

applicants := []Applicant{}
...
fmt.Scan(&firstName, &lastName, &GPA)
applicants = append(applicants, Applicant{firstName, lastName, GPA})

Now my task is to output only names of first 3 applicants with highest GPA. I already sorted the slice from the best GPA to the worst.

I tried to do output applicants slice like this, but got error:

for _, applicant := range applicants {
    fmt.Println(applicant.secondName + " " + applicant.secondName)
}

Can you help me with slice name output?

Upvotes: 1

Views: 8810

Answers (3)

Ausgefuchster
Ausgefuchster

Reputation: 1178

To get the first 3 with highest GPA you first sort the slice (what you alread did) and then just create a subslice:

func GetTopThree(applicants []Applicant) []Applicant {
    sort.Slice(applicants, func(i, j int) bool {
        return applicants[i].GPA > applicants[j].GPA
    })
    return applicants[:3]
}

To just get the names you can create a new slice

func GetTopThreeNames(applicants []Applicant) []string {
    var topThree []string
    for i := 0; i < int(math.Min(3, float64(len(applicants)))); i++ {
        topThree = append(topThree, applicants[i].firstName)
    }
    return topThree
}

Upvotes: 7

lukasl-dev
lukasl-dev

Reputation: 1118

If you want to map the first names and last names separately, this could be an approach:

func TopThreeNames(applicants []Applicant) [][2]string {
    top := applicants[:int(math.Min(3, float64(len(applicants))))]

    var names [][2]string
    for _, a := range top {
        names = append(names, [2]string{a.firstName, a.secondName})
    }
    return names
}

The function maps each Applicant element to an array of length two, whereby the first element is equal to its first name and the second element to its second name.

For instance (unsafe since the length of the slice could be empty):

names := TopThreeNames(applicants)
    
first := names[0]
fmt.Printf("First name: %s and last name: %s\n", first[0], first[1])

Upvotes: 1

guenhter
guenhter

Reputation: 12167

If your task really is just to print out the names then this is one possible way

  for i := 0; i < 3 && i < len(applicants); i++ {
        fmt.Printf("%s %s\n", applicants[i].firstName, applicants[i].secondName)
    }

Note that the list must be sorted first like is is shown in other posts.

Upvotes: 0

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