CODEWITHSUNDEEP
python
jpy
jpy

Reputation: 169

TypeError: sequence item 1: expected str instance, float found

As I already asked on (Convert dictionary key tuple to string), but this time I have a dict={("name1","name2","name3"):256}

I want my dict to be dict={"name1,name2,name3":256} but when I try this I get an error:

    new_dct = {}
    for k,v in dicts.items():
        new_dct[','.join(k)] = v
**TypeError: sequence item 1: expected str instance, float found**

(i removed all nanS) Any idea?

Upvotes: 0

Views: 8676

Answers (3)

Arifa Chan
Arifa Chan

Reputation: 1017

It's the same like before in Convert dictionary key tuple to string. Just remove 's' in dicts.items() as in your first dict variable or find another typo in your code espescially in element of dict or dicts. The exception (TypeError) could be cause by different reference to your dict or dicts variable. Others' answers already solved it, whether using dict comprehension:

dict = {("name1","name2","name3"):256}
new_dct = {','.join(key): value for key, value in dict.items()}
print(new_dct)

or normal for loop:

dict = {("name1","name2","name3"):256}
new_dct = {}
for key, value in dict.items():
    new_dct[','.join(key)] = value
print(new_dct)

and the result will be same output.

{'name1,name2,name3': 256}

Upvotes: 0

constantstranger
constantstranger

Reputation: 9379

I tried your code with dict renamed as d and used in the loop in place of dicts (the value of which is unclear), and it seems to work fine:

d={("name1","name2","name3"):256}

new_dct = {}
for k,v in d.items():
    new_dct[','.join(k)] = v

print(new_dct)

Output:

{'name1,name2,name3': 256}

Here are a few notes:

  • In the code in your question, you use dicts without showing what value you assigned to it.
  • If (for example) you had initialized dicts using dicts={("name1", 2.0, "name3"):256}, it would raise the exception you have mentioned (TypeError: sequence item 1: expected str instance, float found).
  • You may want to examine the contents of the dictionary that you iterate over just before the loop to ensure the items in the tuple keys are all of type str, otherwise join() may not work.

Upvotes: 0

The Thonnu
The Thonnu

Reputation: 3624

Try this:

d = {("name1", "name2", "name3"): 256}
new_d = {','.join(map(str, k)): v for k, v in d.items()}
print(new_d) # {'name1,name2,name3': 256}

Upvotes: 3

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