How to extract Persian texts with Selenium in Python?

Question

How to extract Persian texts with Selenium in Python?? The name variable should be text, but it seems to be empty

from selenium import webdriver
from selenium.webdriver.common.by import By
website="https://www.digikala.com/product/dkp-3628808/%D8%B1%D9%88%D8%BA%D9%86- 
%D8%B2%DB%8C%D8%AA%D9%88%D9%86-%D8%A8%DB%8C-%D8%A8%D9%88- 
%DA%A9%D8%B1%DB%8C%D8%B3%D8%AA%D8%A7%D9%84-%D8%B7%D9%84%D8%A7%DB%8C%DB%8C-3000- 
%D9%85%DB%8C%D9%84%DB%8C-%D9%84%DB%8C%D8%AA%D8%B1/"
driver = webdriver.Chrome(executable_path=r"C:\Users\Qazal\anaconda3\Lib\site- 
packages\selenium\chromedriver.exe")
driver.get(website)
name=driver.find_element(By.XPATH,'//div[@class="mr- 
4"]//a[@href="https://www.digikala.com/seller/AEVNX/"]')
name=name.text
name=name.encode("utf-8")
print(name)

Answer 1

The Xpath expression //*[@class="mr-4"]/div/a/p is producing the following output:

*emphasized text*from selenium import webdriver
from selenium.webdriver.chrome.service import Service
import time
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.by import By

chrome_options = Options()
chrome_options.add_argument("--no-sandbox")

webdriver_service = Service("./chromedriver") #Your chromedriver path
driver = webdriver.Chrome(service=webdriver_service, options=chrome_options)
url='https://www.digikala.com/product/dkp-3628808/%D8%B1%D9%88%D8%BA%D9%86-%20%20%D8%B2%DB%8C%D8%AA%D9%88%D9%86-%D8%A8%DB%8C-%D8%A8%D9%88-%20%20%DA%A9%D8%B1%DB%8C%D8%B3%D8%AA%D8%A7%D9%84-%D8%B7%D9%84%D8%A7%DB%8C%DB%8C-3000-%20%20%D9%85%DB%8C%D9%84%DB%8C-%D9%84%DB%8C%D8%AA%D8%B1/'
driver.get(url)
driver.maximize_window()
time.sleep(5)
for name in driver.find_elements(By.XPATH,'//*[@class="mr-4"]/div/a/p'):
    print(name.text)

Output:

سراج احسان
رزاقی