Reputation: 5598
I have a page with a large table. At the top of the table I've added several filters for eliminating rows in the table. When someone changes a filter, jQuery processes the changes and shows/hides rows in the table that match the filters.
The processing code starts by showing all the rows in the table. Then, it steps through each filter, and wherever necessary, it hides rows in the table. So, each time the user changes a filter, they will see the entire table momentarily and then watch as the rows disappear until the filtering is complete.
Is there a JavaScript or jQuery function for delaying output to the browser until all processing is complete?
Upvotes: 3
Views: 196
Reputation: 707298
I know you've already accepted an answer, but cloning the table is not how I would choose to implement this. I'd prefer to change the code that modifies the table to not modify it directly. Instead, create an output array that contains the list of modifications you will make to the actual visible table. Then, run your code and have it create this output array (which rows are shown and hidden or any other modifications). Then, when the lengthy part of the code is all done and you have this output array, you simply loop through the final output array and apply the changes. If this last part is all done in one synchronous piece of JS, the viewer will not see the intermediate steps, just the final result.
You should note that there are some characteristics of cloning and operating on it before it's inserted into the document to be aware of:
.clone([withDataAndEvents], [deepWithDataAndEvents])
functionUpvotes: 1
Reputation: 165971
You can clone
the table, perform whatever operations you need to on the clone, and replace the original table once you're done:
var newTable = $("#yourTable").clone();
//Do whatever you need to do to newTable
$("#yourTable").replaceWith(newTable);
Here's a working example.
Upvotes: 5
Reputation: 82594
Here is a crude example: http://jsfiddle.net/YNZJf/
Basically use jquery to change the html, then once finished set it back to you table.
$tmp = $( $('#table').html()));
$tmp.filter(); // do work;
$('#table').html($tmp.html());
Upvotes: 1